(adding the second equation to the first one)
Answer:
1. The domain of f(x) is (–∞, –5) U (–5, ∞).
4. The y-intercept is (0, 2).
5. There is a vertical asymptote at x = –5.
6. The end behavior is x → –∞, f(x) → 0 and x → ∞, f(x) → 0.
Step-by-step explanation:
I got it correct on e2020
<span>Volume of a square = (s)(s)(s) and s=5a+4b
Therefore: (5a+4b)(5a+4b)(5a+4b)=
(25a^2+40ab+16b^2)(5a+4b)=
(125a^3+200a^2b+80ab^2+100a^2b+160ab^2+64b^3)= (125a^3+300a^2b+240ab^2+64b^3)
You just multiple the first time the second and then do so again with the combination of the first two times the second. A little cleaning up and you are left with an equation in terms of a and b.</span>
Answer:
b= -1.6
Step-by-step explanation:
All u do is divide 3 into 74 but 3 cant get into 74 so u do the number the close in that 3 times 24 in that 72 but if u do 25 times 3 that 75 in the number cant be greater so then u know it 24 times 3 then u subtract 74 from 72 in get 2 as the remainder so u have 2 as the hold number in 3 as the nemonator in 24 as the denatorator
