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2 years ago

Write 0.125 as if it was 2 to a power

Mathematics

1 answer:

Westkost [7]2 years ago

4 0

Answer:

$2^{-3}$

Step-by-step explanation:

0.125 as a fraction is 125/1000 or 1/8

1 is the same as $2^{0}$ (anything to the power of 0 is 1)
8 is the same as 2³ (2 × 2 × 2 = 8)
$2^{0}$ ÷ 2³ = $2^{-3}$ (You subtract the powers: 0 - 3 = -3)

Hope this helps!

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5.27 rounded to the nearest tenth

vlabodo [156]

It is 20 because the 5 is in the ones place so the 2 has to be in the 10 place which makes it 20

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3 years ago

Read 2 more answers

Atherine has $54. She plans to spend more than $20 of the money for a painting canvas. The rest will go toward paints. Each tube

horsena [70]

I think that she could buy 3 tubes of paint because that's $25.50 and that gives you 28.50 for the canvas.

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2 years ago

What is the equation for the translation of x2 + y2 = 16 seven units to the right and five units up?

asambeis [7]

Answer:

(x − 7)2 + (y − 5)2 = 16

Step-by-step explanation:

The given circle has equation

$\sf \: x^2+y^2=16x$

The equation of a circle with center (h,k) and radius r units is

$\sf(x-h)^2+(y-k)^2=r^2(x−h)$

$\sf(x-7)^2+(y-5)^2=4^2(x−7)$

$\sf(x-7)^2+(y-5)^2=16(x−7)$

This is the equation that has its center at the origin with radius 4 units.

When this circle is translated seven units to the right and five units up, then the center of the circle will now be at (7,5).

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1 year ago

Find the general solution of the differential equation and check the result by differentiation. (Use C for the constant of integ

atroni [7]

Answer: $y=Ce^(^3^t^{^9}^)$

Step-by-step explanation:

Beginning with the first differential equation:

$\frac{dy}{dt} =27t^8y$

This differential equation is denoted as a separable differential equation due to us having the ability to separate the variables. Divide both sides by 'y' to get:

$\frac{1}{y} \frac{dy}{dt} =27t^8$

Multiply both sides by 'dt' to get:

$\frac{1}{y}dy =27t^8dt$

Integrate both sides. Both sides will produce an integration constant, but I will merge them together into a single integration constant on the right side:

$\int\limits {\frac{1}{y} } \, dy=\int\limits {27t^8} \, dt$

$ln(y)=27(\frac{1}{9} t^9)+C$

$ln(y)=3t^9+C$

We want to cancel the natural log in order to isolate our function 'y'. We can do this by using 'e' since it is the inverse of the natural log:

$e^l^n^(^y^)=e^(^3^t^{^9} ^+^C^)$

$y=e^(^3^t^{^9} ^+^C^)$

We can take out the 'C' of the exponential using a rule of exponents. Addition in an exponent can be broken up into a product of their bases:

$y=e^(^3^t^{^9}^)e^C$

The term e^C is just another constant, so with impunity, I can absorb everything into a single constant:

$y=Ce^(^3^t^{^9}^)$

To check the answer by differentiation, you require the chain rule. Differentiating an exponential gives back the exponential, but you must multiply by the derivative of the inside. We get:

$\frac{d}{dx} (y)=\frac{d}{dx}(Ce^(^3^t^{^9}^))$

$\frac{dy}{dx} =(Ce^(^3^t^{^9}^))*\frac{d}{dx}(3t^9)$

$\frac{dy}{dx} =(Ce^(^3^t^{^9}^))*27t^8$

Now check if the derivative equals the right side of the original differential equation:

$(Ce^(^3^t^{^9}^))*27t^8=27t^8*y(t)$

$Ce^(^3^t^{^9}^)*27t^8=27t^8*Ce^(^3^t^{^9}^)$

QED

I unfortunately do not have enough room for your second question. It is the exact same type of differential equation as the one solved above. The only difference is the fractional exponent, which would make the problem slightly more involved. If you ask your second question again on a different problem, I'd be glad to help you solve it.

7 0

2 years ago

Which expression is equivalent to 2(x^2-1) + 3x(x-4) (please show work)

Tema [17]

Answer:

5x^2-12x-2

Step-by-step explanation:

Use distributive property, then add like terms. See file below for steps.

4 0

2 years ago