How do you find the solutions of the equation 2sin^2(x)=1

1 answer:

3 0

Solve for x:
2 sin^2(x) = 1

Divide both sides by 2:
sin^2(x) = 1/2

Take the square root of both sides:
sin(x) = 1/sqrt(2) or sin(x) = -1/sqrt(2)

Take the inverse sine of both sides:
x = 2 π n_1 + (3 π)/4 for n_1 element Z or x = 2 π n_2 + π/4 for n_2 element Z or sin(x) = -1/sqrt(2)

Take the inverse sine of both sides:
Answer: x = 2 π n_1 + (3 π)/4 for n_1 element Z or x = 2 π n_2 + π/4 for n_2 element Z or x = 2 π n_3 + (5 π)/4 for n_3 element Z or x = 2 π n_4 + (7 π)/4 for n_4 element Z

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What are 5 fractions that can simplify to 2/5

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4/10
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A fruit company delivers its fruit in two types of boxes: large and small. a delivery of 5 large boxes and 3 small boxes has a t

Hoochie [10]

Let's let the weight of a large box be L, and the weight of a small box be S.

We know that 5 large boxes and 3 small boxes is 120kg, so:
5L + 3S = 120

We also know that 7 large boxes and 9 small boxes is 234kg, so:
7L + 9S = 234

You can multiply the first equation by 3 to get:
15L + 9S = 360

See how now both equations have 9S? We can now subtract one from the other:
(15L+9S) - (7L+9S) = 360-234
8L = 126
L = 15.75

Now sub this value back into an equation:
(5x15.75) + 3S = 120
3S = 41.25
S = 13.75

Double check these values
(7x15.75) + (9x13.75)
= 110.25 + 123.75
=234, which is consistent with above.

So a large box is 15.75kg, and a small box is 13.75kg.

Hope this helped

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3 years ago

Make t as the subject!! HELP MEE

Umnica [9.8K]

Answer:

t = (p^2/mn) - 1/n

Step-by-step explanation:

Here, we want to make t the subject of the formula

we start by equating both sides so as to remove the root

we have this as;

m(t + n)/t = p^2

m(t + n) = tp^2

mt + mn = tp^2

mn = tp^2 - mt

mn = t(p^2-m)

t = (p^2 - m)/mn

t = p^2/mn - 1/n

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Are all lines of symmetry also diagonals? explain.

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What are the zeros of the quadratic function? f(x)=3x2−300 Enter your answers in the boxes.

nata0808 [166]

Hi there!

We can find the zeros of a function by solving f(x) = 0. We find the following:

$3 {x}^{2} - 300 = 0$
Add 300 to both sides.

$3 {x}^{2} = 300$
Divide by 3.

${x}^{2} = 100$
Take the root and minus root of both sides.

$x = \sqrt{100} = 10 \\ or \\ x = - \sqrt{100} = - 10$

Therefore, the zeros are
x = 10 and x = -10.

~ Hope this helps you!

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