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(6y^2 - 3y^3 + 5)(7y^5)
Use the distributive property
=(6y^2)(7y^5) + (-3y^3)(7y^5) + (5)(7y^5)
= 42y^7 - 21y^8 + 35y^5
= -21y^8 + 42y^7 + 35y^5
Good luck with your studies buddy!
Answer
The statment true about the image be
The measure of ∠TRU is 72° .
Reason
As shown in the image
∠QRU = 90°
∠ TRQ = 18°
Now ∠QRU be written as the sum of the ∠ TRQ and ∠TRU .
Thus it becomes
∠QRU = ∠ TRQ + ∠TRU
put the value ∠QRU and ∠ TRQ
we get
90° = 18 ° + ∠TRU
Solving the above
∠TRU = 90° - 18°
∠TRU = 72 °
Therefore the measure of ∠TRU is 72 °.
Hence proved
Answer:
15.9??
Step-by-step explanation:
Answer:
52x + 26y + 20z
Step-by-step explanation:
Assuming you needed the answer to be simplified!
The equation can be used to determine t, the weight of the textbooks is t = 0.7w
Given:
let
Total weight = w
Weight of notebook = n
Weight of backpack = b
Weight of textbook = t
w = n + b + t
where
n = 4 pounds
b = 2 pounds
t = 0.7w
So
w = 4 + 2 + 0.7w
w - 0.7w = 4 + 2
0.3w = 6
w = 6/0.3
w = 20
Recall,
t = 0.7w
= 0.7(20)
= 14 pounds
Therefore, the weight of the textbook is 14 pounds
Learn more about equation:
brainly.com/question/4916384
