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3 years ago

9

What's the variable of 23x4=c

1 answer:

lara [203]3 years ago

6 0

Answer:

c=23x4

Step-by-step explanation:

Step 1: Flip the equation.

c=23x4

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Identify the polygon with vertices A(5,0), B(2,4), C(−2,1), and D(1,−3), and then find the perimeter and area of the polygon. HE

inn [45]

Answer:

Part 1) The polygon is a square

Part 2) The perimeter is equal to $20\ units$

Part 3) The area is equal to $25\ units^{2}$

Step-by-step explanation:

we have

$A(5,0), B(2,4), C(-2,1),D(1,-3)$

Plot the points

see the attached figure

we know that

the formula to calculate the distance between two points is equal to

$d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}$

Find the distance AB

$A(5,0),B(2,4)$

substitute in the formula

$d=\sqrt{(4-0)^{2}+(2-5)^{2}}$

$d=\sqrt{(4)^{2}+(-3)^{2}}$

$d=\sqrt{25}$

$AB=5\ units$

Find the distance BC

$B(2,4), C(-2,1)$

substitute in the formula

$d=\sqrt{(1-4)^{2}+(-2-2)^{2}}$

$d=\sqrt{(-3)^{2}+(-4)^{2}}$

$d=\sqrt{25}$

$BC=5\ units$

Find the distance CD

$C(-2,1),D(1,-3)$

substitute in the formula

$d=\sqrt{(-3-1)^{2}+(1+2)^{2}}$

$d=\sqrt{(-4)^{2}+(3)^{2}}$

$d=\sqrt{25}$

$CD=5\ units$

Find the distance AD

$A(5,0),D(1,-3)$

substitute in the formula

$d=\sqrt{(-3-0)^{2}+(1-5)^{2}}$

$d=\sqrt{(-3)^{2}+(-4)^{2}}$

$d=\sqrt{25}$

$AD=5\ units$

we have that

AB=BC=CD=AD

Find the distance BD (diagonal)

$B(2,4),D(1,-3)$

substitute in the formula

$d=\sqrt{(-3-4)^{2}+(1-2)^{2}}$

$d=\sqrt{(-7)^{2}+(-1)^{2}}$

$BD=\sqrt{50}\ units$

<em>Verify if the polygon is a square</em>

If the triangle BDA is a right triangle, then the polygon is a square

Applying the Pythagoras theorem

$BD^{2}=AD^{2}+AB^{2}$

substitute

$(\sqrt{50})^{2}=5^{2}+5^{2}$

$50=50$ -----> is true

so

The triangle BDA is a right triangle

therefore

The polygon is a square

<em>Find the Area of the polygon</em>

The area of a square is equal to

$A=b^{2}$

we have

$b=5\ units$

$A=5^{2}=25\ units^{2}$

<em>Find the perimeter of the polygon</em>

The perimeter of a square is equal to

$P=4b$

we have

$b=5\ units$

$P=4(5)=20\ units$

6 0

3 years ago

Suppose that a cyclist began a 374 mi ride across a state at the western edge of the state, at the same time that a car traveli

kherson [118]

This is the concept of relative speed; We are required to calculate the speed of the car and the bicycle.
Distance between the car and Bicycle=374 miles
Time they met=5.5 hr
Speed traveled by bicycle=x
Speed traveled by car=x+33.4334
Relative speed=x+(x+33.4334)=(2x+33.4334) mph
Distance=speed*time
374=(2x+33.4334)*5.5
374=11x+183.8837
collecting like term we get:
374-183.8837=11x
11x=190.1163
thus;
x=(190.1163)/(11)
x=17.2833 mph
thus the speed of the bicycle was x=17.2833 mph
The speed of the car was (x+33.4334)=(17.2833+33.4334)=50.7167 mph

4 0

4 years ago

Solve for p<br>6 = 3 + 3p<br>P=

garik1379 [7]

Answer:

1

Step-by-step explanation:

6=3+3p

6-3=3p

3=3p

3/3=p

1=p

7 0

4 years ago

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Answer the question below <br> i need helpp

loris [4]

Answer:

Step-by-step explanation:

C. lol

4 0

3 years ago

Please help me answer these !!

elena55 [62]

Just get the app photo math it tells you the answer to go math math books and more

6 0

3 years ago