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2 years ago

Factorize 5r⁸t⁵ - 3r⁴t⁴

Mathematics

1 answer:

Wewaii [24]2 years ago

7 0

Factor r 4 t 4 out of 5 r 8 t 5 − 3 r 4 t 4 . r 4 t 4 ( 5 r 4 t − 3 )

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Which equation represents the relationship shown in the graph below?

fomenos

I believe the answer is B
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4 years ago

Determine the measure of angle j: angle k: & angle: l

Vikki [24]

Answer:

17=J

L= 180-17

= 163

K=163

L=163

J=17

Step-by-step explanation:

3 0

3 years ago

Anyone, I need help... Just answer the 6 (c)....and also proper working.☺️

Ainat [17]

Answer:

(i) The area of the rabbit cage when the width is 5.2 m is 81.5 m²

(ii) The area of the rabbit cage if Wilson has 40 meters of wire mesh is 75 m²

Step-by-step explanation:

(i) The given relation of the area, A to the width P of the rabbit cage is A = 3·p²

The graph of the function between the values of 0 and 6 inclusive is found as follows;

A, 3·p²

0, 0

1, 1

2, 12

3, 27

4, 48

5, 75

6, 108

Please find attached the graph of A to 3·p²

From the graph, we have when the the width, p, of the rabbit cage = 5.2, the area, A ≈ 81.5 m²

The area of the rabbit cage when the width is 5.2 m = 81.5 m²

(ii) Also from the graph given that the total wire mess with Wilson = 40 meters, we have;

The formula for the perimeter of the cage = The formula for the perimeter of a rectangle = 2×length + 2×width

The formula for the perimeter of the cage = 2×3×p + 2× p = 8·p

Where the total length of the wire mesh available = 40 meters for the cage

The 40 meters of wire mesh will be used round the perimeter of the cage

∴ 40 m. = 8·p

p = 40/8 = 5 m.

At p = 5 m. the area is given as A = 75 m².

Therefore, the area of the rabbit cage if Wilson has 40 meters of wire mesh = 75 m².

5 0

3 years ago

a bean plant grows at a constant rate for a month. after 10 days, the plant is 30 centimeters tall. after 20 days, the plant is

ANTONII [103]

Answer:

$(y-30)=2(x-10)$

Step-by-step explanation:

We have been given that a bean plant grows at a constant rate for a month. after 10 days, the plant is 30 centimeters tall. after 20 days, the plant is 50 centimeters tall.

First of all we will find slope of our line using given points.

$m=\frac{y_2-y_1}{x_2-x_1}$

Upon substituting coordinates of our given points in slope formula we will get,

$m=\frac{50-30}{20-10}$

$m=\frac{20}{10}=2$

Therefore, slope of our given line is 2.

Since the equation of a line in point slope form is $(y-y_1)=m(x-x_1)$ .

Upon substituting m=2 and coordinates of one point in above equation we will get,

$(y-30)=2(x-10)$

Therefore, the equation that models the height of the plant (y) after x days will be $(y-30)=2(x-10)$ .

5 0

3 years ago

Read 2 more answers

Which row of the input/output table is incorrect?

Dahasolnce [82]

Row D because if you plug in 10 for x you get 17 not 15z

7 0

3 years ago

Factorize 5r⁸t⁵ - 3r⁴t⁴​

Factorize 5r⁸t⁵ - 3r⁴t⁴