You are given the equation 36 = 9x² + 4y². You are asked to find the slopes of the asymptotes of the hyperbola. A hyperbola has the following general equation x²/a² + y²/b² = 1. the goal here is to find the slopes of the hyperbolic equation. So divide both sides by 36
36 = 9x² + 4y²
(1/36)[36 = 9x² + 4y²]
1 = x²/4 + y²/9
a² = 4
a = 2
and
b² = 9
b = 3
To find the slope, divide a/b and you will get 2/3.
Let the required equation be y = mx + c; where y = 1, m = f'(0), x = 0
f(a) = sec(a)
f'(a) = sec(a)tan(a)
f'(0) = sec(0)tan(0) = 0
y = mx + c
1 = 0(0) + c
c = 1
Therefore, required equation is
y = 1.
Answer:
If your answer is multiple choice, try to look for a graph that matches these intercepts. I hope this helped you. Have a great rest of your day!
Answer:
168
Step-by-step explanation:
Sum the parts of the ratio, 6 + 7 = 13 parts
Divide the total number of students by 13 to find the value of one part of the ratio.
364 ÷ 13 = 28 ← value of 1 part of the ratio, thus
number of girls = 6 × 28 = 168
Answer:
X would equal 1.5
Step-by-step explanation:
if 12 divided by 2 equals 6, then you have to find what's half of 3 which is 1.5
