Answer:
d = -8
Step-by-step explanation:
Isolate the variable, d. Note the equal sign, what you do to one side, you do to the other. Divide -4 from both sides of the equation:
d = -8 is your answer.
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(will give brainliest) In right ∆ABC with m∠B=30°, AC = 4. find HB.
1 answer:
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First lets look at our graph of y = cos x
***First picture***
Next lets look at a <span>vertical stretch.
***Second picture***
To vertically stretch y = cos x, we need to multiply cos by a number greater than 1. I am going to use 2.
Standard Form: y = cos x (Red Line)
Vertical Stretch: y = 2 cos x (Blue Line)
Lets look at a vertical shrink
***Third picture***
To create a vertical shrink, you multiply the cos by a number less than 1. I am going to use .5
</span>Standard Form: y = cos x (Red Line)
Vertical Shrink: y = .5 cos x (Green Line)
Now lets look at horizontal stretch.
***Forth picture.***
To create a horizontal stretch, you multiply the x by a value less than 1. I am going to use .5
Standard Form: y = cos x (Red Line)
Vertical Stretch: y = .5 cos x (Orange Line)
Finally, to create a horizontal shrink, you multiply the x by a value greater than 1. I am going to use 2.
***Fifth picture.***
Standard Form: y = cos x (Red Line)
Vertical Shrink: y = 2 cos x (Purple Line)
***First picture***
Next lets look at a <span>vertical stretch.
***Second picture***
To vertically stretch y = cos x, we need to multiply cos by a number greater than 1. I am going to use 2.
Standard Form: y = cos x (Red Line)
Vertical Stretch: y = 2 cos x (Blue Line)
Lets look at a vertical shrink
***Third picture***
To create a vertical shrink, you multiply the cos by a number less than 1. I am going to use .5
</span>Standard Form: y = cos x (Red Line)
Vertical Shrink: y = .5 cos x (Green Line)
Now lets look at horizontal stretch.
***Forth picture.***
To create a horizontal stretch, you multiply the x by a value less than 1. I am going to use .5
Standard Form: y = cos x (Red Line)
Vertical Stretch: y = .5 cos x (Orange Line)
Finally, to create a horizontal shrink, you multiply the x by a value greater than 1. I am going to use 2.
***Fifth picture.***
Standard Form: y = cos x (Red Line)
Vertical Shrink: y = 2 cos x (Purple Line)
ANSWER
The orthocenter is
<u>EXPLANATION</u>
The orthocenter is the point of intersection of all the altitudes of a triangle.
If it is a right angle triangle then the orthocenter is the point at which the <em>right angle is made.</em>
If it is not a right angle triangle, then you have to find the equations of any two of the altitudes and solve simultaneously.
So you must first check to see if it is a right angle triangle that way you do not have to do bunch work.
The given triangle has vertices ,
, and
.
Since the denominator is zero, the slope is undefined.
If the slope of a straight line is undefined, then that line is <em>parallel to the y-axis</em>. In other words, it is a <em>vertical line</em>.
if a straight line has a slope of zero, that line is parallel to the <em>x-axis</em> or it is <em>horizontal.</em>
From the slopes we can see that side KL of the triangle is horizontal and side JK is vertical. This two sides will meet at right angles at K.
See graph.
Therefore the coordinates of K, is the orthocenter of the given triangle.
