Answer:
A = 153.94 sq mi
Step-by-step explanation:
In this scenario, we would be starting from the center point and searching the area of a square since the distance in every direction would the same 7 mi. This 7-mile distance would be our radius in this scenario. We now need to use the formula for the Area of a circle to calculate the search area. This formula is the following
A = 
A = 
A = 
A = 153.94 sq mi
A total of 153.94 square miles must be searched.
<em>Look</em><em> </em><em>at</em><em> </em><em>the</em><em> </em><em>attached</em><em> </em><em>picture</em>
<em>Hope</em><em> </em><em>it</em><em> </em><em>will</em><em> </em><em>help</em><em> </em><em>you</em>
<em>Good</em><em> </em><em>luck</em><em> </em><em>on</em><em> </em><em>your</em><em> </em><em>assignment</em>
Answer:
2 ( a + 7)
Step-by-step explanation:
2a + 14
both 2a and 14 are divisible by 2
2a/a = a
14/2 = 7
2( a + 7) = 2a + 14
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-Chetan K
Assume ladder length is 14 ft and that the top end of the ladder is 5 feet above the ground.
Find the distance the bottom of the ladder is from the base of the wall.
Picture a right triangle with hypotenuse 14 feet and that the side opposite the angle is h. Then sin theta = h / 14, or theta = arcsin 5/14. theta is
0.365 radian. Then the dist. of the bot. of the lad. from the base of the wall is
14cos theta = 14cos 0.365 rad = 13.08 feet. This does not seem reasonable; the ladder would fall if it were already that close to the ground.
Ensure that y ou have copied this problem accurately from the original.
The correct answer is: [C]: " p = 6.25 h " .
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Explanation:
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It is clear that "pay" is a function of "hours worked" ;
So, we can eliminate: "Choice [B]: " h = <span>6.25p" .
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Try, Choice [A]: " </span>p = h + 12.5 " ; and 14.50 ≠ 12.50 ; (12.50 is the amount shown in the table. So, we can already eliminate "Choice [A]".
<span>_____________________________________________
Now that we have eliminated choices [A] and [B];
we are left with choices: [C] and [D]:
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Consider choice [C]: " </span><span>p = 6.25h " ;
</span> when "h = 2" ; does: "p = 12.5" (as shown on table)?? ;
i.e. " 12.5 =? 6.25 * (2) ?? Yes! This choice is a POSSIBILITY.
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Consider choice [D]: " p = 12.5h" .
When "h = 2, does "p = 12.5" (as shown on table)? No!
→ We can see from this very answer choice
(the equation itself) that when "h = 2" ;
the value of "p" is DOUBLE [that of "12.5"].
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The correct answer is: Answer choice: [C]: " <span>p = 6.25 h " .
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