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3 years ago

A mason is a person who builds structures with bricks, stone, cement block, or tile. A mason usually uses

Mathematics

1 answer:

pogonyaev3 years ago

3 0

Answer: I think it can be D

hopfully this helps :)

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If the measure of a tangent-chord angle is 74, then what is the measure of the intercepted arc inside the angle

Vedmedyk [2.9K]

The measure of the intercepted arc is twice the measure of the tangent-chord angle:
2×74° = 148°

The measure of the intercepted arc is 148°.

7 0

3 years ago

Read 2 more answers

5x + 4m = 43my + 6 solve for m

pav-90 [236]

9514 1404 393

Answer:

m = (5x -6)/(43y -4)

Step-by-step explanation:

Subtract 4m+6 to separate m-terms from other terms.

5x +4m -(4m +6) = 43my +6 -(4m +6)

5x -6 = 43my -4m

5x -6 = m(43y -4) . . . . factor out m

(5x -6)/(43y -4) = m . . . . divide by the coefficient of m

7 0

2 years ago

What is the standard deviation of the following data? If necessary, round your answer to two decimal places.

blsea [12.9K]

Total numbers=10
mean(average)=14.8
standard deviation=3.4254
variance_standard deviation)=11.73333
population standard deviation=3.24962
variance(population standard deviation)=10.56

3 0

3 years ago

passes through A(-3, 0) and B(-6, 5). What is the equation of the line that passes through the origin and is parallel to ?

goblinko [34]

Answer:

Equation of line , 5x + 3y = 0

Step-by-step explanation:

The slope of a line passing through points (x₁,y₁) and (x₂,y₂) is given by $\frac{y_2-y_1}{x_2-x_1}$

Here points are given by (-3,0) and (-6,5)

Slope $=\frac{5-0}{(-6)-(-3)}=\frac{-5}{3}$

The slope of parallel lines are same. So slope of required line $=\frac{-5}{3}$

Equation of a line with slope m passing through origin is given by

y =mx

So equation of line, $y=\frac{-5}{3}x\\\\3y=-5x\\\\5x+3y=0$

Equation of line , 5x + 3y = 0

4 0

3 years ago

Read 2 more answers

If, P(x,y) is a point on the unit circle determined by real number δ, then tanδ = what

Lisa [10]

$\bf sin(\theta)=\cfrac{opposite}{hypotenuse}
=\cfrac{y}{r}
=\cfrac{1}{csc(\theta)}
\\ \quad \\\\
% cosine
cos(\theta)=\cfrac{adjacent}{hypotenuse}
=\cfrac{x}{r}
=\cfrac{1}{sec(\theta)}
\\ \quad \\\\
% tangent
tan(\theta)=\cfrac{opposite}{adjacent}
=\cfrac{y}{x}
=\cfrac{sin(\theta)}{cos(\theta)}$

$\bf cot(\theta)=\cfrac{adjacent}{opposite}
=\cfrac{x}{y}
=\cfrac{cos(\theta)}{sin(\theta)}
\\ \quad \\\\
% cosecant
csc(\theta)=\cfrac{hypotenuse}{opposite}
=\cfrac{r}{y}
=\cfrac{1}{sin(\theta)}
\\ \quad \\\\
% secant
sec(\theta)=\cfrac{hypotenuse}{adjacent}
=\cfrac{r}{x}
=\cfrac{1}{cos(\theta)}\\\\
-------------------------------\\\\
P(x,y)\implies \delta\qquad tan(\delta)=\cfrac{y}{x}$

5 0

3 years ago