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siniylev [52]
3 years ago
5

Sport

Mathematics
1 answer:
katen-ka-za [31]3 years ago
3 0
10% because walking is only 10 percent of the hrs
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Can someone pleaseeee help if you’re correct I’ll give u brainlist
tangare [24]

55 degrees. If you add the other three angles together you get 305. Considering that a circle is 360 degrees, you would subtract those two and get 55.

4 0
3 years ago
Can someone please help me with #37
kolbaska11 [484]
Using the diagram, we can conclude that the radius is 10 feet, and the height is 6 feet.

Plug in the values for radius and height into the equation.
V = π10^2*6
Simplify in terms of pi.
V = 600π
Round pi to 3.14 and multiply by 600.
V = 1,884

1,884 cubic feet is your answer.
In the image you provided, I do not see a fourth option that includes 1,884 cubic feet. I would assume that the camera did not take a full picture of the answer choices.
4 0
3 years ago
Expression equivalent?<br>8x2 - 5x + 3x(4 - 2x)​
aleksklad [387]

Answer:

Step-by-step explanation:

8x² - 5x + 3x(4 - 2x) =8x² - 5x + 3x*4 - 3x*2x

= 8x² - 5x + 12x - 6x²

Now add the like terms

= 8x² - 6x² - 5x + 12x

= 2x² + 7x

5 0
3 years ago
Read 2 more answers
An elevator containing five people can stop at any of seven floors. What is the probability that no two people exit at the same
elena-s [515]

Answer:

Approximately 0.15 (360 / 2401.) (Assume that the choices of the 5 passengers are independent. Also assume that the probability that a passenger chooses a particular floor is the same for all 7 floors.)

Step-by-step explanation:

If there is no requirement that no two passengers exit at the same floor, each of these 5 passenger could choose from any one of the 7 floors. There would be a total of 7 \times 7 \times 7 \times 7 \times 7 = 7^{5} unique ways for these 5\! passengers to exit the elevator.

Assume that no two passengers are allowed to exit at the same floor.

The first passenger could choose from any of the 7 floors.

However, the second passenger would not be able to choose the same floor as the first passenger. Thus, the second passenger would have to choose from only (7 - 1) = 6 floors.

Likewise, the third passenger would have to choose from only (7 - 2) = 5 floors.

Thus, under the requirement that no two passenger could exit at the same floor, there would be only (7 \times 6 \times 5 \times 4 \times 3) unique ways for these two passengers to exit the elevator.

By the assumption that the choices of the passengers are independent and uniform across the 7 floors. Each of these 7^{5} combinations would be equally likely.

Thus, the probability that the chosen combination satisfies the requirements (no two passengers exit at the same floor) would be:

\begin{aligned}\frac{(7 \times 6 \times 5 \times 4 \times 3)}{7^{5}} \approx 0.15\end{aligned}.

5 0
2 years ago
Which answer shows 9 times 10 Superscript negative 5 written in standard form? –0.000009 –0.00009 0.0009 0.00009
julsineya [31]

Answer: 0.00009

Step-by-step explanation:

9*10^-5 = 9/(10^5) = 9/100000 = 0.00009

4 0
3 years ago
Read 2 more answers
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