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atroni [7]
3 years ago
11

SOME HELP ME PLS. I WILL MARK U BRAINLIEST

Mathematics
1 answer:
vesna_86 [32]3 years ago
5 0

Answer: i think they are 2.75 a piece but im nott 100% sure

Step-by-step explanation:

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Pls help and show workings due ASAP
Fed [463]

Answer:

goodluck

Step-by-step explanation:

7 0
3 years ago
The coordinates of a point and its images are given. Is the reflection in the
Lemur [1.5K]

Answer:

The reflection is in the y-axis cause the y point went from -7 to 7 and the x point stayed the same.

4 0
3 years ago
Solve for x: 3 over 3x+ 1 over x+4= 10 over 7x
hram777 [196]

Answer:

3

Step-by-step explanation:

3/3x + 1/x+4 = 10/7x

3/3x + 1/x+4 = 10/7x , x=0,x=-4

1/x + 1/x+4 = 10/7x

1/x + 1/x+4 - 10/7x = 0

7(x+4)+7x-10(x+4) / 7x*(x+4) = 0

7x+28+7x-10x-40 / 7x*(x+4) = 0

4x-12 / 7x*(x+4) = 0

4x-12=0

4x-=12

x=3,x=0,x=-4

x=3

7 0
4 years ago
In 1898 L. J. Bortkiewicz published a book entitled The Law of Small Numbers. He used data collected over 20 years to show that
attashe74 [19]

Answer:

(a) The probability of more than one death in a corps in a year is 0.1252.

(b) The probability of no deaths in a corps over 7 years is 0.0130.

Step-by-step explanation:

Let <em>X</em> = number of soldiers killed by horse kicks in 1 year.

The random variable X\sim Poisson(\lambda = 0.62).

The probability function of a Poisson distribution is:

P(X=x)=\frac{e^{-\lambda}\lambda^{x}}{x!};\ x=0,1,2,...

(a)

Compute the probability of more than one death in a corps in a year as follows:

P (X > 1) = 1 - P (X ≤ 1)

             = 1 - P (X = 0) - P (X = 1)

             =1-\frac{e^{-0.62}(0.62)^{0}}{0!}-\frac{e^{-0.62}(0.62)^{1}}{1!}\\=1-0.54335-0.33144\\=0.12521\\\approx0.1252

Thus, the probability of more than one death in a corps in a year is 0.1252.

(b)

The average deaths over 7 year period is: \lambda=7\times0.62=4.34

Compute the probability of no deaths in a corps over 7 years as follows:

P(X=0)=\frac{e^{-4.34}(4.34)^{0}}{0!}=0.01304\approx0.0130

Thus, the probability of no deaths in a corps over 7 years is 0.0130.

6 0
3 years ago
ZEFG and ZGFH are a linear pair, mZEFG = 3n+ 21, and mZGFH = 2n + 34. What are mZEFG and mZGFH?
marysya [2.9K]

Answer:

The answer is below

Step-by-step explanation:

∠EFG and ∠GFH are a linear pair, m∠EFG = 3n+ 21, and m∠GFH = 2n + 34. What are m∠EFG and m∠GFH?

Solution:

Two angles are said to form a linear pair if they share a base. Linear pair angles are adjacent angles formed along a line as a result of the intersection of two lines. Linear pairs are always supplementary (that is they add up to 180°).

m∠EFG = 3n + 21, m∠GFH = 2n + 34. Both angles form linear pairs, hence:

m∠EFG + m∠GFH = 180°

3n + 21 + (2n + 34) = 180

3n + 2n + 21 + 34 = 180

5n + 55 = 180

5n = 125

n = 25

Therefore, m∠EFG = 3(25) + 21 = 96°, m∠GFH = 2(25) + 34 = 84°

7 0
3 years ago
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