We're finding the function of (p+3), which means wherever there's an x, we're replacing it with (p+3).
2 (p+3)^2 + 3 (p+3) + 6
Foil out (p+3)^2.
2 (p^2 + 6p + 9) + 3 (p+3) + 6
Distribute.
2p^2 + 12p + 18 + 3p + 9 + 6
Add like terms.
g (p+3) = 2p^2 + 15p + 33
The cross section would be a semicircle because a cross section of the whole thing would be a circle
Hope this helps
Fruit adult = 26
fruit total = 52
vegetable child = 14
total child = 40
total adult = 50
The square footage of the path is 47.1 ft²
The area of a circle is:
A = πr²
Where r is the radius of the circle.
Let us assume that the pool is a circle.
Given that the pool has a radius (r₁) of 7 feet and a path 1 foot wide would go round the pool.
Radius of pool and cement path (r₂) = 7 ft + 1 ft = 8 ft.
The square footage of the path = πr₂² - πr₁² = π*8² - π * 7² = 47.1 ft²
Hence The square footage of the path is 47.1 ft²
Find out more at: brainly.com/question/23328170
Answer:
There is no clear relationship between the number of times students arrive late and the distances they live from school.
Step-by-step explanation:
By looking at the graph, there is no clear direction or association that the graph has. Therefore, there is no clear relationship between the variables being compared.
