To solve this, you need to isolate/get the variable "u" by itself in the inequality: u = unknown number
2u - 3 < 1 Add 3 on both sides
2u - 3 + 3 < 1 + 3
2u < 4 Divide 2 on both sides to get "u" by itself
u < 2 (u is any number less than 2)
When the inequality sign is >/< (greater than/less than), the dot/endpoint is an open/unfilled circle.
When the inequality sign is ≥/≤ (greater than or equal to/less than or equal to), the dot is a closed/filled circle.
u < 2
Start making a ray by placing an open circle on 2(click on the dot/endpoint to change it to be open if it isn't already), then have the ray point left where the numbers would be decreasing because "u" is any number less than 2. If you can place the end of the ray at the end of the number line.
Answer:
A) A = 1; B = 0; C = 20
Step-by-step explanation:
The standard form for a quadratic is
Ax^2 +Bx +C=0
We are given
1/4x^2 + 5 = 0
Rewriting
1/4x^2 +0x+ 5 = 0
A = 1/4 B=0 C=5
We can multiply each side by 4
4(1/4x^2 +0x+ 5) = 0*4
x^2 +0x+ 20 = 0
A = 1 B=0 C=20
Answer:
you answer is 2 because 2 - 6 is -4
Answer:
For the code we have 3 selections.
The first selection is a digit that must be odd, so the options are {1, 3, 5, 7 ,9}
So we have 5 options.
The second selection is a letter from the set of all the letters (27) minus the set of the vowels (5)
So here we have 27 - 5 = 22 options
The third selection is also a letter from the previous set, but because each letter can be used only one time, and in the previous selection we already selected one of the letters, in this selection we have a letter less than in the previous selection.
Here we have 22 - 1 = 21 options.
The total number of combinations (of possible codes) is equal to the product of the number of options for each selection:
C = 5*22*21 = 2310.
There are 2310 different possible codes
Factor it out (x+2)(x-1)
Set each of these equal to zero to get -2,1 as your answers
