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zavuch27 [327]
2 years ago
13

Someone please help I don’t understand sad face

Mathematics
2 answers:
Bess [88]2 years ago
6 0
-1 cus its -1 becus u -1 so u get -1
bija089 [108]2 years ago
4 0
Someone please help I don’t understand sad face : it’s -1
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Please help ASAP 15 POINTS BRAINIEST ANSWER!!
maxonik [38]
1) around 1300

2) around 30

3) a. about 500
    b. about 2600

Hope this helps you!
7 0
3 years ago
I need help:/ I’m in college
lesantik [10]

Step-by-step explanation:

Amount of acid = 14.9% of 331 mL solution

= 0.149×(331 mL)

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3 0
3 years ago
Solve for x. Round to the nearest tenth, if necessary. 1.8 & x
Valentin [98]

Answer:

x ≈ 1.4

Step-by-step explanation:

Using the sine ratio in the right triangle

sin50° = \frac{opposite}{hypotenuse} = \frac{RS}{RT} = \frac{x}{1.8} ( multiply both sides by 1.8 )

1.8 × sin50° = x , then

x ≈ 1.4 ( to the nearest tenth )

7 0
2 years ago
I need help please 25 points for whoever helps me
34kurt
Yuto is correct because he isolated the variable correctly and reversed the inequality symbol.

x < 3
3 0
3 years ago
The quantity a varies directly with b and c and inversely with dThe quantity d is tripledWhich of the following must be true for
EastWind [94]

Answer:

We have the next relation:

A = (b*d)/c

because we have direct variation with b and d, but inversely variation with c.

Now, if we have 3d instead of d, we have:

A' = (b*(3d))/c

now, we want A' = A. If b,c, and d are the same in both equations, we have that:

3bd/c = b*d/c

this will only be true if b or/and d are equal to 0.

If d remains unchanged, and we can play with the other two variables we have:

3b'd/c' = bd/c

3b'/c' = b/c

from this we can took that: if c' = c, then b' = b/3, and if b = b', then c' = 3c.

Of course, there are other infinitely large possible combinations that are also a solution for this problem where neither b' = b or c' = c

6 0
3 years ago
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