Tyler concludes that 5x² will always have a larger output for the same value of x.
<u>Look at the graph below and the table given</u>
Take a random value: x = 0
Here, 1 > 0, making 2^x > 5x²
Hence, 2^x is greater than 5x² at this point. making Tyler's point not applicable.
Disagree with Tyler's point.
2a + b^2
2(3) + 2^2
6 + 4
10
(x-3)/y
((12)-3)/(3)
9/3
3/1
3
Answer:
is standard equation of hyperbola with vertices at (0, ±9) and foci at (0, ±11).
Step-by-step explanation:
We have given the vertices at (0, ±9) and foci at (0, ±11).
Let (0,±a) = (0,±9) and (0,±c) = (0,±11)
The standard equation of parabola is:
From statement, a = 9
c² = a²+b²
(11)² = (9)²+b²
121-81 = b²
40 = b²
Putting the value of a² and b² in standard equation of parabola, we have
which is the answer.
Answer:
Step-by-step explanation:
7x - 382 = 3x - 161
4x - 382 = -161
4x = 221
x = 55.25