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Hatshy [7]
3 years ago
12

Hannah finds that the amount of time she spends studying for her history tests affects her grade on the test. Which statement de

scribes the relationship Hannah is observing?
Mathematics
2 answers:
Zepler [3.9K]3 years ago
7 0

Answer:

what are the multiple choices so i can answer it? plz and thank you

Step-by-step explanation:

elena-s [515]3 years ago
4 0

Answer:

Step-by-step explanation:

There are not statements. But...

If she studies more her grade is better.

The more she studies, the more her grade goes up.

The less she studies, the more her score goes down.

Just some guesses for you. Match up with your statements.

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To make a sports drink for the football team, Jaylen filled \dfrac9{10}
Scilla [17]

The total gallons of sports drink Jaylen made using 9/10 of a large cooler with water and 6 cups of sports drink concentrate is 3.75 gallons

<h3>Total gallons</h3>

  • Water in the large cooler = 9/10

Space remaining = 1 - 9/10

= 10-9 / 10

= 1/10

1/10 = 6 cups

  • Total gallons of sport drink = x

6 cups / total = 1/10

6 × 10 = total × 1

60 cups = total

Cups to gallons:

16 cups = 1 gallon

Total gallons of sport drink, x = 60 cups / 16

= 3.75 gallons

Complete question:

To make a sports drink for the football team, Jaylen filled 9/10 of a large cooler with water. Then, he filled the remaining space with 6 cups of sports drink concentrate. How many gallons of sports drink did Jaylen make?

Learn more about total gallons:

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3 0
2 years ago
Identify each expression with a sum of x2 + 3x +1.
Yuki888 [10]

Answer:

There are no like terms.

Step-by-step explanation:

5 0
3 years ago
Which property is illustrated by the equation 3 (m n) = (3 m) n?
Sav [38]
Associative property
8 0
3 years ago
Read 2 more answers
Prove that is here<br><img src="https://tex.z-dn.net/?f=1%20-%20cos%20%7B2%7Da%20%5Cdiv%201%20-%20sin%20a%7B2%7D%20%20%3D%20tan%
garri49 [273]

\\ \sf\longmapsto \dfrac{1-cos2A}{1-sin2A}

<h3>LHS</h3>

\boxed{\sf \dfrac{cosA}{sinA}=cotA}

\\ \sf\longmapsto \dfrac{1-cos2A}{1-sin2A}

\\ \sf\longmapsto 1-cot2A

\\ \sf\longmapsto 1-\dfrac{1}{tan2A}

\\ \sf\longmapsto \dfrac{tan2A-1}{tan2A}

\\ \sf\longmapsto tan2A

8 0
3 years ago
A ladder 16 feet long is leaning against the wall of a tall building. The base of the ladder is moving away from the wall at a r
svet-max [94.6K]

Answer:

a. 0.588

b. 0.0722

c. 4.576 sqft/sec

Step-by-step explanation:

Let b and h denote the base and height as indicated in the diagram. By pythagoras theorem, h^2 + b^2 = 16^2 = 256 \dotsc\;(1) because it is a right angle triangle.

It is given that \frac{db}{dt} = 1

Now differentiate (1) with respect to t (time) :

\displaystyle{2h\frac{dh}{dt} + 2b\frac{db}{dt} = 0 \implies \frac{dh}{dt} = -\frac{b}{h} \frac{db}{dt}}

\displaystyle{=-\frac{b}{\sqrt{256 - b^2}} \frac{db}{dt} = -\frac{8}{13.856} \times 1 = -0.588}

The minus sign indicates that the value of h is actually decreasing. The required answer is 0.588.

b. From the diagram, infer that 16 \sin{\theta} = b. When b = 8, then \theta = \arcsin{0.5} = \ang{30}.

Differentiate the above equation w.r.t t

\displaystyle{16 \cos{\theta} \frac{d\theta}{dt} = \frac{db}{dt} \implies \frac{d\theta}{dt} = \frac{1}{16 \cos{\theta}} = \frac{1}{13.856} = \mathbf{0.0722}}

c. The area of the triangle is given by A = 0.5\times h \times b. Differentiating w.r.t t,

\displatstyle{\frac{dA}{dt} = 0.5 b \frac{dh}{dt} + 0.5 h \frac{db}{dt}}

Plugging in b = 8, h = 13.856, \frac{dh}{dt} = -0.588,

\frac{dA}{dt} = -2.352 + 6.928 = \mathbf{4.576 ft^2/sec}

8 0
4 years ago
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