Answer:
y-3
Problem:
What is the remainder when the dividend is xy-3, the divisor is y, and the quotient is x-1. ?
Step-by-step explanation:
Dividend=quotient×divisor+remainder
So we have
xy-3=(x-1)×(y)+remainder
xy-3=(xy-y)+remainder *distributive property
Now we just need to figure out what polynomial goes in for the remainder so this will be a true identity.
We need to get rid of minus y so we need plus y in the remainder.
We also need minus 3 in the remainder.
So the remainder is y-3.
Let's try it out:
xy-3=(xy-y)+remainder
xy-3=(xy-y)+(y-3)
xy-3=xy-3 is what we wanted so we are done here.
Answer:
1) Distributive Property of Multiplication (The terms are distributed)
2) Addition property of equality (Adding 14 to both sides)
3) Simplifying (We simplified the expression)
4) Division property of equality (Dividing both sides by 6)
Answer:
Step-by-step explanation:
Using formula 
a= 650
b= 800
and c is the unkown
Answer:h=60×2
=120
Step-by-step explanation:
Answer:
8.6002300X10^7
Step-by-step explanation:
