Sqrt of 125
10^2 +b^2= 15^2
100 +b^2=225
B^2=125
No perfect square for 125 so leave it in radical form
-6(2x - 4) = -6*(2x) -6*(-4) = -12x + 24
-(12x - 6) + 18 = -12x + 6 + 18 = -12x + 24
-3(4x - 3) + 15 = -3*(4x) -3*(-3) + 15 = -12x + 9 + 24 = -12x + 24
-4(3x + 6)
= -4*(3x) -4*(6) = -12x -24
All the expressions gave the same answer as -12x + 24, except for the last expression.
So, -4(3x + 6)
is not equivalent to the others.
Answer:
where is ques
Step-by-step explanation:
Answer:
2 PI
Step-by-step explanation:
so the segment appears to be 1/4th of the circle, being shown by the pi/2 as displayed. Thus, we can solve for the circumfrence and divide that answer by 4. since 2*pi*r is the way to calculate this problem, it would be 2 times pi times 4, giving us the whole circumfrence of 8pi. Divide that by 4, and you have the solution of 2 pi
