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FromTheMoon [43]
3 years ago
14

PLEASE HELP ASAP! WILL GIVE BRAINLEIST! Find the area of the shaded region. Use pi = 3.14

Mathematics
1 answer:
Semmy [17]3 years ago
4 0

Answer:

Step-by-step explanation:

Square

The side length of the square = 8 cm

The area of the square = s^2

The area of the square = 8^2 = 64

Circle

r = d/2

r = 8/2

r = 4

Area of the circle = pi r^2

Area of the circle = 3.14 * 16

Area of the circle = 50.24

Shaded Area

Area of the Shaded area = area Square - Area Circle

                                          = 64 - 40.24

                                          = 23.76

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Answer:

(1,4)

Step-by-step explanation:

Let's this of y=\sqrt{x} which is it's parent function.

How do we get to y=-\sqrt{x-1}+4 from there?

It has been reflected about the a-axis because of the - in front of the square root.

It has been shifted right 1 unit because of the -(1) in the square root.

It has been moved up 4 units because of the +4 outside the square root.

In general:

y=a(x-h)^2+k has the following transformations from the parent:

Moved right h units if h is positive.

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Moved up k units if k is positive.

Moved down k units if k is negative.

If a is positive, it has not been reflected.

If a is negative, it has been reflected about the x-axis.

a also tells us about the stretching factor.

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It new graphed was the parent function but reflected over x-axis and shifted right 1 unit and moved up 4 units.

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I am Lyosha [343]

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What is the volume of the sphere that has a diameter of 3? use 3.14 for pie​
aev [14]

Hey ! there

Answer:

  • <u>1</u><u>1</u><u>3</u><u>.</u><u>0</u><u>4</u><u> </u><u>unit </u><u>cube</u>

Step-by-step explanation:

In this question we are provided with a sphere <u>having</u><u> </u><u>radius </u><u>3 </u><u>units </u>and <u>value </u><u>of </u><u>π </u><u>is </u><u>3.</u><u>1</u><u>4</u><u> </u><u>.</u><u> </u>And we're asked to find the<u> </u><u>volume</u><u> of</u><u> </u><u>sphere</u><u> </u><u>.</u>

For finding volume of sphere , we need to know its formula . So ,

\qquad \qquad \: \underline{\boxed{ \frak{Volume_{(Sphere)} =  \dfrac{4}{3} \pi r {}^{3} }}}

<u>Where</u><u> </u><u>,</u>

  • π refers to <u>3.</u><u>1</u><u>4</u>

  • r refers to <u>radius</u><u> of</u><u> sphere</u>

<u>Sol</u><u>u</u><u>tion </u><u>:</u><u> </u><u>-</u>

Now , we are substituting value of π and radius in the formula ,

\quad \longrightarrow \qquad \: \dfrac{4}{3}   \times 3.14 \times (3) {}^{3}

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\quad \longrightarrow \qquad \: \dfrac{4}{3}  \times 3.14 \times 3 \times 3 \times 3

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\quad \longrightarrow \qquad \: \dfrac{4}{ \cancel{3}}  \times 3.14 \times 3 \times 3 \times  \cancel{3}

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Multiplying 12.56 and 9 :

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Answer:

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Since adding a positive makes a negative number stay negative, it equals -4.

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