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3 years ago

What’s 1+1? Is it 929? Uwu

Mathematics

1 answer:

Allisa [31]3 years ago

3 0

Answer:

No it's 2 Lol not 929 UwU

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Can someone help me plz

galina1969 [7]

A= about 75 cents -- This is because you would figure out what 5% is equal to (.05). Then, you would do .05 x 14.90 to get the amount of sales tax you will be paying. By doing this you will get .745 which is approximately .75 which would become 75 cents

b= $15.65 -- For this one, you would do the cents (.75) plus the total (14.90) So you would do 14.90+.75 which = 15.65.

Hope this helped :)

4 0

3 years ago

What is the midpoint of the line segment with endpoints (-2, -4) and (4,6)?

prohojiy [21]

Answer:

(1,1)

Step-by-step explanation:

use the midpoint formula to find the midpoint of the line segment

7 0

4 years ago

What is the answer to -2x- x +8

Musya8 [376]

The answer is -3x+8 hope this helped!

5 0

3 years ago

Read 2 more answers

Find the volume of the region between the planes x plus y plus 2 z equals 2 and 4 x plus 4 y plus z equals 8 in the first octant

Alex787 [66]

Find the intercepts for both planes.

Plane 1, x + y + 2z = 2:

$y=z=0\implies x=2\implies (2,0,0)$

$x=z=0\implies y=2\implies(0,2,0)$

$x=y=0\implies 2z=2\implies z=1\implies(0,0,1)$

Plane 2, 4x + 4y + z = 8:

$y=z=0\implies4x=8\implies x=2\implies(2,0,0)$

$x=z=0\implies4y=8\impliesy=2\implies(0,2,0)$

$x=y=0\implies z=8\implies(0,0,8)$

Both planes share the same x- and y-intercepts, but the second plane's z-intercept is higher, so Plane 2 acts as the roof of the bounded region.

Meanwhile, in the (x, y)-plane where z = 0, we see the bounded region projects down to the triangle in the first quadrant with legs x = 0, y = 0, and x + y = 2, or y = 2 - x.

So the volume of the region is

$\displaystyle\int_0^2\int_0^{2-x}\int_{\frac{2-x-y}2}^{8-4x-4y}\mathrm dz\,\mathrm dy\,\mathrm dx=\displaystyle\int_0^2\int_0^{2-x}\left(8-4x-4y-\frac{2-x-y}2\right)\,\mathrm dy\,\mathrm dx$

$=\displaystyle\int_0^2\int_0^{2-x}\left(7-\frac72(x+y)\right)\,\mathrm dy\,\mathrm dx=\int_0^2\left(7(2-x)-\frac72x(2-x)-\frac74(2-x)^2\right)\,\mathrm dx$

$=\displaystyle\int_0^2\left(7-7x+\frac74 x^2\right)\,\mathrm dx=\boxed{\frac{14}3}$

3 0

3 years ago

Please help giving Brainiest!!

Firdavs [7]

Answer:8 shaded in size 1/4 the area 1/2

Step-by-step explanation:if wrong sorry.

8 0

2 years ago