81\3 using the distributive property

In the diagram m angle ACB = 61 Find m angle BCD

Marina86 [1]

we are given that

angle(ACF)=90

angle(ACB)=61

sum of all angles along any line is 180

so, we get

angle(ACF)+angle(ACD)=180

we can plug value

90+angle(ACD)=180

angle(ACD)=90

now, we can use formula

angle(ACD)=angle(ACB)+angle(BCD)

now, we can plug values

and we get

90=61+angle(BCD)

90-61=61-61+angle(BCD)

angle(BCD)=29................Answer

7 0

3 years ago

Read 2 more answers

Data collected at Toronto Pearson International Airport suggests that an exponential distribution with mean value 2725hours is a

Ivan

Answer:

a) What is the probability that the duration of a particular rainfall event at this location is at least 2 hours?

We want this probability"

$P(X >2) = 1-P(X\leq 2) = 1-(1- e^{-0.367 *2})=e^{-0.367 *2}= 0.48$

At most 3 hours?

$P(X \leq 3) = F(3) = 1-e^{-0.367*3}= 1-0.333 =0.667$

b) What is the probability that rainfall duration exceeds the mean value by more than 2 standard deviations?

$P(X > 2.725 + 2*5.540) = P(X>13.62) = 1-P(X$

What is the probability that it is less than the mean value by more than one standard deviation?

$P(X$

Step-by-step explanation:

Previous concepts

The exponential distribution is "the probability distribution of the time between events in a Poisson process (a process in which events occur continuously and independently at a constant average rate). It is a particular case of the gamma distribution". The probability density function is given by:

$P(X=x)=\lambda e^{-\lambda x}$

The cumulative distribution for this function is given by:

$F(X) = 1- e^{-\lambda x}, x\ geq 0$

We know the value for the mean on this case we have that :

$mean = \frac{1}{\lambda}$

$\lambda = \frac{1}{Mean}= \frac{1}{2.725}=0.367$

Solution to the problem

Part a

What is the probability that the duration of a particular rainfall event at this location is at least 2 hours?

We want this probability"

$P(X >2) = 1-P(X\leq 2) = 1-(1- e^{-0.367 *2})=e^{-0.367 *2}= 0.48$

At most 3 hours?

$P(X \leq 3) = F(3) = 1-e^{-0.367*3}= 1-0.333 =0.667$

Part b

What is the probability that rainfall duration exceeds the mean value by more than 2 standard deviations?

The variance for the esponential distribution is given by: $Var(X) =\frac{1}{\lambda^2}$

And the deviation would be:

$Sd(X) = \frac{1}{\lambda}= \frac{1}{0.367}= 2.725$

And the mean is given by $Mean = 2.725$

Two deviations correspond to 5.540, so we want this probability:

$P(X > 2.725 + 2*5.540) = P(X>13.62) = 1-P(X$

What is the probability that it is less than the mean value by more than one standard deviation?

For this case we want this probablity:

$P(X$

8 0

4 years ago

PLEASE HURR ANSWER RIGHT I HAVE TO TURN IT IN TODAY!!!!!!!!!!!!!!OR IM IN BIG TROUBLE WILL GIVE BRAINLIEST IF ANSWER RIGHT AND 5

Alekssandra [29.7K]

33/40 is the experimental probability.

8 0

3 years ago

Choose the point-slope form of the equation below that represents through the points (-3,2) and (2,1)

s2008m [1.1K]

Answer:

-1/4

Step-by-step explanation:

2-1 over -3-1 = 1/-4

3 0

3 years ago

The figure is made from squares of different sizes.Find the area of A if the side of each of the two indentical smallest square

Temka [501]

Answer:

The area of square A is 256 cm²

Step-by-step explanation:

The four sides of a square are equal in length
Area of a square = side × side

In the given figure

∵ The sides of the square E = 2 cm each

∵ The sides of the square F = 2 cm each

∵ The side of square D is the sum of the sides of squares E and F

∴ The sides of the square D = 2 + 2 = 4 cm each

∵ The side of square C is the sum of the sides of squares E and D

∴ The sides of square C = 2 + 4 = 6 cm each

∵ The side of square B is the sum of the sides of squares C, E, and F

∴ The sides of square B = 6 + 2 + 2= 10 cm each

∵ The side of square A is the sum of the sides of squares B, F, and D

∴ The sides of square A = 10 + 2 + 4= 16 cm each

∵ Area of square A = side × side

∴ Area of square A = 16 × 16

∴ Area of square A = 256 cm²

∴ The area of square A is 256 cm²

3 0

3 years ago