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alex41 [277]
2 years ago
11

What is the equation of the line that passes through the point (–2,7) and has a slope of zero?

Mathematics
1 answer:
scZoUnD [109]2 years ago
4 0

Answer:

y = 7

Step-by-step explanation:

Given:

x1 = -2

y1 = 7

slope (m) = 0

y - y1 = m ( x - x1 )

y - 7 = 0 ( x - (-2) )

y - 7 = 0 ( x + 2 )

y - 7 = 0

y = 7

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Enter the slope of the line through the points (5, 2) and (-3, -7).
ehidna [41]

Answer:

m=9/8 or 1 1/8

Step-by-step explanation:

m= change in y over change in x

2 - -7 = 9

5 - -3 = 8

3 0
3 years ago
Sarah bought a bike that costs $260. She a coupon that was worth $55 off the cost of any bike. Use the expression $260 + (-55) t
Rudiy27

Answer:

205 dollars for the bike

Step-by-step explanation:

4 0
3 years ago
In ΔSTU, the measure of ∠U=90°, the measure of ∠T=32°, and US = 5.8 feet. Find the length of ST to the nearest tenth of a foot.
murzikaleks [220]

Answer:

10.9451≈10.9 feet

Step-by-step explanation:

sinT= hypotenuse/ opposite = x/5.8

sin32= x/5.8

x*sin 32=5.8

x=5.8/sin 32= <u>10.9451≈10.9 feet</u>

8 0
3 years ago
the sum of 2 consecutive integers is at most the difference between nine times the smaller and 5 times the larger
Reil [10]
<h2>Answer:</h2>

x\geq 3 \ and \ x+1 \geq 4

<h2>Step-by-step explanation:</h2>

The question in this problem is:

<em>The sum of 2 consecutive integers is at most the difference between nine times the smaller and 5 times the larger. What are the numbers?</em>

<em />

First of all, let's name the first variable x which is the smaller number. Accordingly, the lager number will be x+1 given that those numbers are consecutive. On the other hand<em> at most </em>conveys the idea of an inequality, which is:

\leq \\ which \ means \ less \ than

So:

1. The sum of 2 consecutive integers can be written as:

v+(v+1)

2. Nine times the smaller and 5 times the larger can be written as:

9v-5(v+1)

Finally, the whole statement:

The sum of 2 consecutive integers is at most the difference between nine times the smaller and 5 times the larger:

x+(x+1) \leq 9x-5(x+1) \\ \\ x+x+1\leq 9x-5x-5 \\ \\ 2x+1 \leq 4x-5 \\ \\ 6 \leq 2x \\ \\

x+(x+1) \leq 9x-5(x+1) \\ \\ x+x+1\leq 9x-5x-5 \\ \\ 2x+1 \leq 4x-5 \\ \\ 6 \leq 2x \\ \\ \frac{6}{2} \leq \frac{2x}{2} \\ \\ 3 \leq x \\ \\ x\geq 3 \\ \\ and \\ \\ x+1 \geq 4

The two numbers are:

x\geq 3 \ and \ x+1 \geq 4

6 0
3 years ago
I need help please and thank you
omeli [17]
Oof I’m not quite sure how to do that
8 0
3 years ago
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