Answer:
Sorry I don't know
Step-by-step explanation:
Given that the printer depreciates at the rate of 14% p.a. This has been modeled by the function V=2400(1-0.14)^t, this follows an exponential form given by
y=a(b)^x
where:
V=y
a=2400
b=1-0.14
x=t
thus:
<span>Part A: Explain what the parameter 2,400 represents in the equation of the function.
</span>The parameter 2400 represents the initial value of the printer at time t=0. This is the original value.
<span>Part B: What is the factor by which the printer depreciates each year?
The factor of depreciation is 14% percent. This is the rate at which the printer depreciates and it accounts for the value of the printer at the end of every year.
</span><span>Part C: Amy also considered purchasing a printer that costs $4,000 and depreciates by 25% each year. Which printer will have more value in 5 years?
Value after 5 years of the $2400 printer that depreciates at 14% per year will be:
V(t)=2400(1-0.14)^5=$1,129.025
Value after 5 years of the $4000 printer that depreciates at 25% per year will be:
F(t)=4000(1-0.25)^t
F(5)=4000(1-0.25)^5=$949.22
The printer that costs $2400 will be more valuable compared to the printer that cost $4000</span>
First to figure out the problem you need to distribute the 3 and the 4. You get, 3x-3-8=4+4x+5. Now you need to combine the coefficients. After doing this you will have 3x-11=9+4x. Now to get x by itself you need to subtract 3x from both sides. You will have -11=9+x. Then you subtract 9 from both sides and you end up with x=-20
3(x-1)-8=4(1+x)+5
3x-3-8= 4+4x+5
3x-11=9+4x
-3x -3x
-11=9+x
-9 -9
-20=x