Solution:
As region bounded by y-axis, the line y=6, and the line y=1/2 is a line segment of definite length on y-axis.
We consider a line , one dimensional if it's thickness is negligible.
So, Line is two dimensional if it's thickness is not negligible becomes a quadrilateral.
So, Area (region bounded by y-axis, the line y=6, and the line y=1/2 is a line segment of definite length on y-axis)= Area of line segment between [,y=6 and y=1/2.]= 6-1/2=11/2 units if we consider thickness of line as negligible.
Answer:100
Step-by-step explanation:
Answer:
Step-by-step explanation:
8xC-Bdivide by c
Answer:
25+24= 49coins 49÷2.5 is 19.5 so there are 19.5 dimes in the bag I believe
Answer:
y = 5
Step-by-step explanation:
A line parallel to the x- axis has equation
y = c
Where c is the value of the y- coordinates the line passes through
The line passes through (1, 5) with y- coordinate of 5, thus
y = 5 ← equation of line