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omeli [17]
3 years ago
5

A mowing company charges $840 plus $17 per hour. Another moving company charges $760 plus $22 per hour. How long is a job that c

osts the same no matter which company is used?
Mathematics
1 answer:
Korvikt [17]3 years ago
3 0

Answer: 16 hours

Step-by-step explanation:

The two equations are:

840 + 17x

and

760 + 22x

with x being the amount of hours

840 + 17x = 760 + 22x  

-760

80 + 17x = 22x

-17x

80 = 5x

/5

16 = x

840 + 17(16) = 1,112

760 + 22(16) = 1,112

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A baby girl weighed 18 lb 10 oz at 11 months and 20 lb 2 oz at 12 months. How much weight did the baby gain during this month?
SVEN [57.7K]

Answer:

B

Step-by-step explanation:

6 oz, 19lb

1 lb, 20lb

2 oz, 20lb 2oz

6oz+2oz+1lb= 1lb 8oz

4 0
3 years ago
What are the domain and range of the function x^2-2x^2-4?
jonny [76]

{x}^{2}  - 2 {x}^{2}  - 4 \\  -  {x}^{2}  - 4

The Quadratic Function has the domain as the set of all real numbers.

For the range, start from minimum value to maximum value.

But because the parabola is downward as a < 0. Thus, there are no minimum value but the maximum value instead.

Therefore the range is y <= -4

7 0
3 years ago
justin is redoing his bathroom floor with tiles measuring 6 in. by 13 in. the floor has an area of 8,500 in2. what is the least
Softa [21]


Frist you do 6*13

Which equals 78

Then you do 8,500/78

Which equals <span>108.974358974</span>

<span>Then you round it to 109</span>

<span>and there's your awnser</span>

<span>
</span>

3 0
3 years ago
Read 2 more answers
Simplify: cos2x-cos4 all over sin2x + sin 4x
GrogVix [38]

Answer:

\frac{\cos\left(2x\right)-\cos\left(4x\right)}{\sin\left(2x\right)+\sin\left(4x\right)}=\tan\left(x\right)

Step-by-step explanation:

\frac{\cos\left(2x\right)-\cos\left(4x\right)}{\sin\left(2x\right)+\sin\left(4x\right)}

Apply formula:

\cos\left(A\right)-\cos\left(B\right)=-2\cdot\sin\left(\frac{A+B}{2}\right)\cdot\sin\left(\frac{A-B}{2}\right) and

\sin\left(A\right)+\sin\left(B\right)=2\cdot\sin\left(\frac{A+B}{2}\right)\cdot\sin\left(\frac{A-B}{2}\right)

We get:

=\frac{-2\cdot\sin\left(\frac{2x+4x}{2}\right)\cdot\sin\left(\frac{2x-4x}{2}\right)}{2\cdot\sin\left(\frac{2x+4x}{2}\right)\cdot\cos\left(\frac{2x-4x}{2}\right)}

=\frac{-\sin\left(\frac{2x-4x}{2}\right)}{\cos\left(\frac{2x-4x}{2}\right)}

=\frac{-\sin\left(\frac{-2x}{2}\right)}{\cos\left(\frac{-2x}{2}\right)}

=\frac{-\sin\left(-x\right)}{\cos\left(-x\right)}

=\frac{-\cdot-\sin\left(x\right)}{\cos\left(x\right)}

=\frac{\sin\left(x\right)}{\cos\left(x\right)}

=\tan\left(x\right)

Hence final answer is

\frac{\cos\left(2x\right)-\cos\left(4x\right)}{\sin\left(2x\right)+\sin\left(4x\right)}=\tan\left(x\right)

6 0
3 years ago
What is the aquare root of 200​
Anton [14]

Answer:

=10\sqrt{2}

Step-by-step explanation:

Simplify the radical by breaking the radicand up into a product of known factors.

Like this :

5 0
3 years ago
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