The equation of line a is y=−14x+3. If line b runs perpendicular to line a and passes through (2, 6), what would be the equation
1 answer:
You might be interested in
Answer:
Step-by-step explanation:
separate with like terms
the first fraction can be left alone as it can't be simplified any further
the second fraction can be written as w⁹ ÷ w¹ , when the bases are the same and division is involved subtract the powers: 9 - 1 = 8, so it's simplified to w⁸
the third fraction can be written as m⁵ ÷ m⁹, subtract the powers: 5 - 9 = -4, so it's simplified to m⁻⁴
putting it together:
The vertex-form equation is
y = a(x+1)² -16
Putting in the y-intercept values, we have
-15 = a(0+1)² -16
1 = a . . . . . . . . . . . add 16
Then the x-intercepts can be found where y=0.
0 = (x+1)² -16
16 = (x+1)²
±4 = x+1
x = -1 ± 4 = {-5, 3}
y = a(x+1)² -16
Putting in the y-intercept values, we have
-15 = a(0+1)² -16
1 = a . . . . . . . . . . . add 16
Then the x-intercepts can be found where y=0.
0 = (x+1)² -16
16 = (x+1)²
±4 = x+1
x = -1 ± 4 = {-5, 3}