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3 years ago

7

A domain of [-4, -2, 1

1 answer:

UNO [17]3 years ago

5 0

what???????

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Given this quadratic equation, 2x^2-x-28=0,

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Step-by-step explanation:

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3 years ago

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I need help with this my brain cant comprehend

Rom4ik [11]

The function is symmetric in the line that goes trough the top. The top is on t=2.5 seconds. If you want to know on which time the height is equal to 15 feet, you draw a line on that height in the graph and see where it crosses. That is at t=1.25 and t=3.75

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3 years ago

<img src="https://tex.z-dn.net/?f=%20%7Bx%7D%5E%7B2%7D%20%20%2B%202x%20%3D%200" id="TexFormula1" title=" {x}^{2} + 2x = 0" alt=

Alex

Answer:

$\textbf{Hello!}$

$\Longrightarrow2^2+2z=0$

$\Longrightarrow x_{1,\:2}=\frac{-2\pm \sqrt{2^2-4\cdot \:1\cdot \:0}}{2\cdot \:1}$

$\Longrightarrow \sqrt{2^2-4\cdot \:1\cdot \:0}$

$\Longrightarrow =\sqrt{2^2-0}$

$\Longrightarrow =\sqrt{2^2}$

$\Longrightarrow=2$

$\Longrightarrow x_{1,\:2}=\frac{-2\pm \:2}{2\cdot \:1}$

$\Longrightarrow x_1=\frac{-2+2}{2\cdot \:1},\:x_2=\frac{-2-2}{2\cdot \:1}$

$\Longrightarrow\frac{-2+2}{2\cdot \:1}$

$\Longrightarrow =\frac{0}{2\cdot \:1}$

$\Longrightarrow =\frac{0}{2}$

$=0$

$\Longrightarrow\frac{-2-2}{2\cdot \:1}$

$\Longrightarrow =\frac{-4}{2\cdot \:1}$

$\Longrightarrow =\frac{-4}{2}$

$\Longrightarrow =-\frac{4}{2}$

$=-2$

$x=0,\:x=-2\Longleftarrow$

$\underline{HOPE ~IT~HELPS}$

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3 years ago

Whic graph shows y=x^2-3 ?

Snowcat [4.5K]

The answer is A because pintasan y is -3

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3 years ago

The gcf of 14 and 22

Finger [1]

The GCF is 2
Hope this helps!

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3 years ago

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