All categories

2 years ago

I will give Brainiest if you are right

Mathematics

2 answers:

Vadim26 [7]2 years ago

8 0

Answer:

19.5º

Step-by-step explanation:

Every triangle is equal to 180º for all angles. So, you add 33.5 + 127 and subtract the sum by 180.

33.5 + 127= 160.5

180- 160.5 = 19.5

So, the angle F is 19.5º

Hope this helps !!

-Ketifa

tino4ka555 [31]2 years ago

7 0

Answer:

look at the picture I sent

You might be interested in

The distance from the green point on the parabola to the parabolas focus is 11. What is the distance from green point to the dir

Lina20 [59]

Answer:

answer 11

Step-by-step explanation:

I think it the right answer

4 0

3 years ago

Helen used 1/4 of her savings for her first year of college. 3/8 of that money was spent on her housing and meals. Which equatio

iren [92.7K]

3/32
just multiply the fractions

8 0

3 years ago

Read 2 more answers

What is the value represented by the digit 8 after 7,824 is divided by 10? help PLEASE 15 Point

8_murik_8 [283]

Answer: 80

Step-by-step explanation:

7824/10 = 782.4

The value represented by 8 is 80 or 8 tens.

7 0

3 years ago

Write an expression to represent "triple the quotient of a number and three."

Furkat [3]

Answer:

3n/3 or 3n÷3

Step-by-step explanation:

since it says triple the quotient of a number, we can use the number n.

To find the quotient means to divide and it's going to be by that numer.....n....... trippled (3)

put them all together and you get 3n/3

4 0

2 years ago

Please see attachment

Dafna11 [192]

Answer:

a) The value of absolute minimum value = - 0.3536

b) which is attained at $x = \frac{1}{\sqrt{2} }$

Step-by-step explanation:

Step(i):-

Given function

$f(x) = \frac{-x}{2x^{2} +1}$ ...(i)

Differentiating equation (i) with respective to 'x'

$f^{l} = \frac{2x^{2} +1(-1) - (-x) (4x)}{(2x^{2}+1)^{2} }$ ...(ii)

$f^{l}(x) = \frac{2x^{2}-1}{(2x^{2}+1)^{2} }$

Equating Zero

$f^{l}(x) = \frac{2x^{2}-1}{(2x^{2}+1)^{2} } = 0$

$\frac{2x^{2}-1}{(2x^{2}+1)^{2} } = 0$

$2 x^{2}-1 = 0$

$2 x^{2} = 1$

$x^{2} = \frac{1}{2}$

$x = \frac{-1}{\sqrt{2} } , x = \frac{1}{\sqrt{2} }$

Step(ii):-

Again Differentiating equation (ii) with respective to 'x'

$f^{ll}(x) = \frac{(2x^{2} +1)^{2} (4x) - 2(2x^{2} +1) (4x)(2x^{2}-1) }{(2x^{2}+1)^{4} }$

put

$x = \frac{1}{\sqrt{2} }$

$f^{ll} (x) > 0$

The absolute minimum value at $x = \frac{1}{\sqrt{2} }$

Step(iii):-

The value of absolute minimum value

$f(x) = \frac{-x}{2x^{2} +1}$

$f(\frac{1}{\sqrt{2} } ) = \frac{-\frac{1}{\sqrt{2} } }{2(\frac{1}{\sqrt{2} } )^{2} +1}$

on calculation we get

The value of absolute minimum value = - 0.3536

Final answer:-

a) The value of absolute minimum value = - 0.3536

b) which is attained at $x = \frac{1}{\sqrt{2} }$

3 0

3 years ago