Question

Two long, parallel wires are separated by a distance of 3.80 cm . The force per unit length that each wire exerts on the other is 4.90×10−5 N/m , and the wires repel each other. The current in one wire is 0.540 A .(a) What is the current in the second wire? (b) Are the two currents in the same direction or in opposite directions?

Answer 1

Answer:

(a). I' = 17.24 A

(b).The current in second wire is in opposite direction compare to first wire.

Explanation:

Given data

r = 0.038 m

$\frac{F}{L} =$ 4.9 × $10^{-5}$ $\frac{N}{m}$

I = 0.54 A

(a). The current in the second wire is calculated as

$I'=\frac{F}{L} \frac{2 \pi r}{\mu I}$

Put all the values in above formula we get

$I' =$ $\frac{ (2) (3.14) (0.038)}{4 \pi (0.54)} 490$

I' = 17.24 A

(b). The current in the two wires is in opposite directions because the wires repeal each other. therefore the current in second wire is in opposite direction compare to first wire.