During takeoff, an airplane goes from 0 to 60 m/s in 10 s.

Physics

1 answer:

Elis [28]1 year ago

8 0

Answer:

see below

Explanation:

acceleration = Δv /Δt

for this situation 60 / 10 = 6 m/s^2

B) vf = vo + at

vf = 0 + 6(3) = 18 m/s after 3 seconds

C) vf = at

60 = 6 ( t) t = 10 seconds ( actually, this was given)

d = 1/2 a t^2

= 1/2 (6) (10)^2 = 300 m

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