Find the value of the probability of the standard normal variable Z corresponding to this area for problems 1-3.
1 answer:
Answer:
Explained below.
Step-by-step explanation:
The complete question is:
Find the value of the probability of the standard normal variable Z corresponding to this area for problems 1-3.
1. P(Z < 1.62)
2. P(Z > -1.57)
3. P(-1.41 < Z < 0.63)
Solution:
Use Excel to solve the problems.
(1)
P(Z < 1.62) =NORM.S.DIST(1.62,TRUE)
= 0.9474
(2)
P(Z > -1.57) = P (Z < 1.57)
=NORM.S.DIST(1.57,TRUE)
= 0.9418
(3)
P(-1.41 < Z < 0.63) = P (Z < 0.63) - P (Z < -1.41)
=NORM.S.DIST(0.63,TRUE) - NORM.S.DIST(-1.41,TRUE)
= 0.7357 - 0.0793
= 0.6564
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Answer:
8 pies and 2 coffees must have been bought.
Step-by-step explanation:
Given that:
10 men bought either a pie or a cup of coffee.
Cost per pie = 60p
Cost per coffee = 50p
Total amount spent = £5.80 * 100 = 580p
Let,
x be the number of pies
y be the number of coffees
According to given statement;
x+y = 10 Eqn 1
60x+50y=580 Eqn 2
Multiplying Eqn 1 by 50
50(x+y=10)
50x+50y=500 Eqn 3
Subtracting Eqn 2 from Eqn 3
(60x+50y)-(50x+50y) = 580-500
60x+50y-50x-50y=80
10x=80
Dividing both sides by 10
Putting x=8 in Eqn 1
8+y=10
y=10-8
y=2
Hence,
8 pies and 2 coffees must have been bought.