The ship movement is an illustration of distance and bearing
The ship is 31.97 miles from its point of departure
<h3>The distance from the point of departure?</h3>
The given parameters are:
- Distance east = 40 milies
- Distance southwards = 70 miles
- Angle = 12 degrees
See attachment for the image of the above parameters
The distance (x) from the point of departure is then calculated using the following cosine function
a^2 = b^2 + c^2 - 2bc * cos(Ф)
So, we have:
x^2 = 40^2 + 70^2 - 2 * 40 * 70 * cos(12)
Evaluate the exponent and the product
x^2 = 6500 - 5477.63
Evaluate the difference
x^2 = 1022.37
Evaluate the exponent
x = 31.97
Hence, the ship is 31.97 miles from its point of departure
Read more about distance and bearing at:
brainly.com/question/24142612
The median for city A is 4 and the median for city B is 5.25.
Answer:

Step-by-step explanation:
Given that,
...(1)
We need to find the value of
.
Put n = 1 to find the first term.

Put n = 2 to find the second term.

Put n = 3 to find the third term.

Put n = 10 to find the tenth term.

It means we need to find the sum of 5,7,9,.....,23.
The formula for the sum of n terms is given by :

We have, n = 10, a = 5 and 
So,

So, the value of
is equal to 280.
Hi,

Now just divide both sides of equation by -4.

Simplify:

Decimal form:

Hope this helps.
r3t40
Answer:
what does it say young buck