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Otrada [13]
2 years ago
14

If odd natural numbers are less than 7, then they are prime numbers.

Mathematics
1 answer:
guajiro [1.7K]2 years ago
5 0
I think true?? i think! im really not sure but yea
You might be interested in
Beginning inventory: $14,320 Merchandise Purchases: $7,880 Goods available for sale: (a) Ending inventory: $11,250 Cost of goods
VikaD [51]

Answer:

$22,200

$10,950

Step-by-step explanation:

Goods available for sale = beginning inventory + Merchandise Purchases

$14,320 +  $7,880  = $22,200

Ending inventory = goods available for sale - ending inventory

$22,200 - $11,250 = $10,950

6 0
3 years ago
If the tank is then field to capacity how many half-gallon bottles how many cords will it make?
lukranit [14]

Answer:

Divide 12 by 4 first to figure out how many gallons are in each 1/4 of the tank. 

12/4=3

So if I added another 1/4 to the capacity:

It could hold 15 gallons. 

All you have to do to find how many half bottles can be filled is to times 15 by two since we are filling half gallon bottles.

15x2=30

30 bottles.

6 0
4 years ago
CALCULUS: For an object whose velocity in ft/sec is given by v(t) = sin(t), what is its distance, in feet, travelled on the inte
rodikova [14]

The linked answer is wrong because that integral gives you the net displacement of the object, not the total distance.

To get the distance, you have to integrate the speed (as opposed to velocity), which involves integrating the absolute value of the velocity function.

\mathrm{distance} = \displaystyle\int_1^5 |\sin(t)| \,\mathrm dt

By definition of absolute value,

|\sin(t)|=\begin{cases}\sin(t)&\text{for }\sin(t)\ge0\\-\sin(t)&\text{for }\sin(t)

Over this particular integration interval,

• sin(<em>t</em> ) ≥ 0 for 1 ≤ <em>t</em> < <em>π</em>, and

• sin(<em>t</em> ) < 0 for <em>π</em> < <em>t</em> ≤ 5

so you end up splitting the integral at <em>t</em> = <em>π</em> as

\mathrm{distance} = \displaystyle\int_1^\pi \sin(t)\,\mathrm dt + \int_\pi^5 (-\sin(t))\,\mathrm dt

Now compute the distance:

\mathrm{distance} = -\cos(t)\bigg|_1^\pi + \cos(t)\bigg|_\pi^5

\mathrm{distance} = -(\cos(\pi) - \cos(1)) + (\cos(5) - \cos(\pi))

\mathrm{distance} = -2\cos(\pi) + \cos(1) + \cos(5) \approx 2.82

making B the correct answer.

7 0
3 years ago
Please helppp!! ill give brainliest &lt;333
hichkok12 [17]

Answer: Area: D. 32\frac{6}{20}

Step-by-step explanation:

Step 1: Convert the Expressions

4\frac{3}{4}*6\frac{4}{5}

\frac{19}{4}*\frac{34}{5}

Step 2: Reduce the Numbers

\frac{19}{4}*\frac{34}{5}

\frac{19}{2}*\frac{17}{5}

Step 3: Multiply

\frac{19}{2}*\frac{17}{5}

\frac{323}{10}

Step 4: Simplify

\frac{323}{10}

32\frac{6}{20}

Please mark brainliest if this helped! :)

4 0
3 years ago
10
Mekhanik [1.2K]

Answer:

ithink 8470 the answer

Step-by-step explanation:

sana nakatulong

3 0
3 years ago
Read 2 more answers
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