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Scrat [10]
2 years ago
8

Olivia does chores every Saturday morning. She spends 1/3 of her time cleaning her room. Of the remaining 2/3 of her time, she s

pends 6/7 of it cleaning the kitchen. How much of Olivia's total time does she spend cleaning the kitchen?]
Mathematics
1 answer:
melomori [17]2 years ago
6 0

Answer:

she spends 9 hours

Step-by-step explanation:

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Find the missing side or angle.<br> Round to the nearest tenth.
LenaWriter [7]

Answer:

6√6 or 14.7

Step-by-step explanation:

8 0
2 years ago
5 Points
goldenfox [79]

Answer:

320 ounces

Step-by-step explanation:

There is 16 ounces in one pound. Multiply 20 x 16 to get 320.

7 0
3 years ago
Read 2 more answers
A real estate agent received 1.5% commission for a house that sold for $250,000. How much was the agent's commission?
vampirchik [111]

Answer:

The answer is B.

Step-by-step explanation:

The answer would be B because dividing 250,000 would get you 25,000 which would be 10% of the total cost. Dividing by 10 again would get you 2500 which would be 1% of the total cost. Divide 2500 by 2 and you'll get 1250. 1250 + 2500 would be 1.5% of the total cost.

8 0
2 years ago
(Pls help me)
Delicious77 [7]

Answer:

\boxed{ \tt{in \:  a  \:  quadratic  \:  equation \: the \: highest \: power \:  is \: 2}} \\ \boxed{ \tt{hence \: she \: was \: not \: correct}}

6 0
2 years ago
Some research suggests that police officers are more likely to make an arrest in the presence of bystanders. If mentally disorde
zmey [24]

Answer:

t=\frac{7.03-3.58}{\frac{9.42}{\sqrt{20}}}=1.638    

p_v =P(t_{(19)}>1.638)=0.0589    

If we compare the p value and the significance level given \alpha=0.05 we see that p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can conclude that the true mean is not significantly higher than 3.58 at 5% of signficance.    

Step-by-step explanation:

Data given and notation    

\bar X=7.03 represent the sample mean

s=9.42 represent the sample standard deviation    

n=20 sample size    

\mu_o =3.58 represent the value that we want to test  

\alpha=0.01 represent the significance level for the hypothesis test.    

z would represent the statistic (variable of interest)    

p_v represent the p value for the test (variable of interest)    

State the null and alternative hypotheses.    

We need to conduct a hypothesis in order to check if the mean is higher than 3.58 :    

Null hypothesis:\mu \leq 3.58    

Alternative hypothesis:\mu > 3.58    

Since we don't know the population deviation, is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:    

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}} (1)    

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".    

Calculate the statistic    

We can replace in formula (1) the info given like this:    

t=\frac{7.03-3.58}{\frac{9.42}{\sqrt{20}}}=1.638    

P-value    

First we need to calculate the degrees of freedom given by:

df=n-1=20-1=19

Since is a right tailed test the p value would be:    

p_v =P(t_{(19)}>1.638)=0.0589    

Conclusion    

If we compare the p value and the significance level given \alpha=0.05 we see that p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can conclude that the true mean is not significantly higher than 3.58 at 5% of signficance.    

7 0
3 years ago
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