<span>Point slope form is (y - y1) = m(x - x1), where m is a slope of 2, and x1 = 0 and y1 = 0 are our point at the origin. Therefore, we can plug in these values to get the point slope equation for our line:
(y – 0) = 2*(x - 0)</span>
Answer:
Step-by-step explanation:
You want to set up a system. We are given some points fo we can set up inputs and outputs. F(0) = 5, given by point (0,5). and F(3)=135, given by point (3,135). The exponential function general equation is F(x)= a(b)^x. plug in out functions into the general equation to get a(b)^0=5 and a(b)^3=135. Then you simplify and solve for a. In the equation a*b^0=5, anything to the power of 0 is 1. so a*1=5. Therefore a=5. we plug in the a to the second equation to find b. 5*b^3=135. b^3=27. b=3 from simplifying. Therefore, the equation should be 5(3)^x. THATS IT!
Answer:
because it will bounce high and hit something.
Step-by-step explanation:
Answer:
Go catipiller
Step-by-step explanation:
