The water that was left after the 20th caravan passed through the pool is 50 m³. Using fractions, the required value is obtained.
<h3>What are fractions?</h3>
A fraction is a rational number that has the required part and whole part of an object.
<h3>Calculation:</h3>
It is given that,
The total volume of the water in the pool is W = 1050 m³
Twenty caravans are traveling across the desert one day apart.
1) On the first day, the camel consumed half of the water in the pool.
Then we can write, water consumed by the camels on the first day = 1/2 × W
So, the remaining water left in the pool = W - W/2 = W/2 ...(i)
2) On the second day, the camel consumed one-third of the water in the pool.
Then, water consumed by the camels on the second day = 1/3 × W/2 = W/6
So, the remaining water left in the pool = W/2 - W/6 = 4W/12 = W/3 ...(ii)
3) On the third day, the camel consumed one-quarter of the water in the pool.
Then, water consumed by the camels on the third day = 1/4 × W/3 = W/12
So, the remaining water left in the pool = W/3 - W/12 = 3W/12 = W/4 ...(iii)
From (i), (ii), and (iii) we can observe that the denominator of the remaining water volume is increased by 1 every next day.
I.e., the general form we can write here is W/(n + 1)
Where W - the volume of the water; n - the number of days it reaches the pool.
Thus, on the 20th day, the camels will consumed the remaining water. I.e.,
The remaining water left in the pool = W/(20 + 1) = W/21
But we have W = 1050 m³
On substituting,
The remaining water left in the pool after the 20th caravan passed through = 1050/21 = 50 m³
Learn more about fractions here:
brainly.com/question/1052420
#SPJ9
