Answer:
h'(x) = (-x² ln x + x² + 1) / (x (x² + 1)^(³/₂))
Step-by-step explanation:
h(x) = ln x / √(x² + 1)
You can either use quotient rule, or you can rewrite using negative exponents and use product rule.
h(x) = (ln x) (x² + 1)^(-½)
h'(x) = (ln x) (-½) (x² + 1)^(-³/₂) (2x) + (1/x) (x² + 1)^(-½)
h'(x) = (-x ln x) (x² + 1)^(-³/₂) + (1/x) (x² + 1)^(-½)
h'(x) = (x² + 1)^(-³/₂) (-x ln x + (1/x) (x² + 1))
h'(x) = (1/x) (x² + 1)^(-³/₂) (-x² ln x + x² + 1)
h'(x) = (-x² ln x + x² + 1) / (x (x² + 1)^(³/₂))
Answer:
132
Step-by-step explanation:
First you need to find the area of both regions (shaded and not shaded)
To find the shaded regions area multiply length by width
20 x 8 = 160
Then find the area of the unshaded region
7 x 4 = 28
Finally subtract the unshaded region from the shaded region
160 - 28 = 132
Answer:
Correct option is (C).
Step-by-step explanation:
Because in figure,
°.°point B is fixed at plane.
.°.Center is B.
& °.° Image is enlargement.
.°. scale factor will be greater than 1
Now,
scale factor = A'B'/AB
= 24/6
= 3
So correct option is (C).
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Answer:
3 students are eating lunches other than salads and sandwiches.
Step-by-step explanation:
To solve this you know that there are 18 students in the cafeteria and 1/6 of them are eating salads and 2/3 are eating sandwiches right? So you would have to think about what 1/6 of 18 is so you know how many students are eating salads, and 1/6 of 18 is 3 so there are 3 students eating salads. Now, you have to find out how many students are eating sandwiches, so you need to know what 2/3 of 18 is. 2/3 of 18 is 12 so now you also know that there are 12 students eating sandwiches. Next, you have to add 12 and 3 and you get 15. Since you know that there are 18 students in the cafeteria, you have to subtract 18 by 15, and you should get 3. So 3 students are eating lunches other than salads or sandwiches.
Hope this helps you! :D
X and y would be 1/1 or 1
