Answer: the boy won 10 games
Step-by-step explanation:
Let's call B as the number of games won by the boy, and F as the number of games won by the father.
We know that, there is a total of 26 games:
B + F = 26.
We know that in each game won by the boy, he wins 8 cents, for every game that the father wins, the boy losses 5 cents, and we know that at the end of the 26 games, the boy did not win or lose any money, so we have:
B*8 + F*(-5) = 0.
Then we have a system of equations:
B + F = 26
8*B - 5*F = 0.
The first step is isolating one of the variables. Let's start isolating F in the first equation:
B + F = 26
F = 26 - B.
Now we can replace this in the second equation:
8*B - 5*F = 0
8*B - 5*(26 - B) = 0
8*B + 5*B - 5*26 = 0
13*B = 5*26
B = 5*26/13 = 5*2 = 10
So the boy won 10 games (then the father won the other 16 games)
Add 121/4 to each side:
x²+11x+121/4 < 121/4-8
x²+11x+121/4 < 89/4
(x+11/2)² < √89/2 ⇒ -√89/2 < x+11/2 < √89/2
-11/2-√89/2 < x < -11/2+√89/2
The answer is -12 hope this helps
Answer:
the number of grams of zinc contain is 78
Step-by-step explanation:
The computation of the number of grams of zinc contain is shown below:
Given that the ratio of zinc to copper is 3:16
And, the jar of the chemical has 416 grams copper
So, the number of zinc grams would be
here we assume the zinc grams be x
Now the equation would be
3 ÷ 16 = x ÷ 416
Now applied the cross multiplication
16x = 416 × 3
x = (416 × 3) ÷ 16
= 78
Therefore the number of grams of zinc contain is 78
