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3 years ago

WILL GIVE A BRAINLIEST PLEASE HELP!!!

1 answer:

7 0

A(n) = a₁.(r)ⁿ⁻¹, where a₁ = 1st term, r= common ratio and n, the rank

In the formula given a₁ = 5, r = 3/2 and n = 6 (we have to find the 6th term value).

a₆ = 5.(3/2)⁶⁻¹ = 5.(3/2)⁵ = 1215/32 (answer C)

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Solve: x=4+(4x-4)1/2

Damm [24]

Answer:

x = 10

Step-by-step explanation:

x = 4 + (4x-4) ^ (1/2)

First, we rewrite the expression:

x = 4 + (4x-4) ^ (1/2)

x = 2 (2+ (x-1) ^ (1/2))

x = 4 + 2 (x-1) ^ (1/2)

From here we get a solution for x = 10

To check it we substitute x = 10 in the expression:

10 = 4 + 2 (10-1) ^ (1/2)

10 = 4 + 2 (9) ^ (1/2)

10 = 4 + 2 (3)

10 = 4 + 6

10 = 10

Answer:

The solution is:

x = 10

8 0

3 years ago

Read 2 more answers

Please answer quickly who ever answers the question correctly will get a brainlyest + 100 points.

bazaltina [42]

Answer:

Step-by-step explanation:

The perimeter is all the side lengths added together

In this case, the

perimeter = x + (x+4) + (x+6) = 3x + 10

The correct answer is the first choice

3 0

2 years ago

If someone finished watching a movie at 1:10 pm and the movie was 1 hour and 38 minutes long what time did the movie start

mixas84 [53]

Answer:

Step-by-step explanation: 11:32

8 0

3 years ago

Read 2 more answers

Simplify each expression<br>4sg/-5g<br>and<br>(8 + 7a) + 4

Yanka [14]

$\dfrac{4sg}{-5g}=-\dfrac{4}{5}\cdor\dfrac{sg}{g}=-\dfrac{4}{5}s\\\\(8+7a)+4=7a+(8+4)=7a+12$

5 0

3 years ago

A college football coach has decided to recruit only the heaviest 15% of high school football players. He knows that high school

Alla [95]

Answer:

The coach should start recruiting players with weight 269.55 pounds or more.

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 225 pounds

Standard Deviation, σ = 43 pounds

We are given that the distribution of weights is a bell shaped distribution that is a normal distribution.

Formula:

$z_{score} = \displaystyle\frac{x-\mu}{\sigma}$

We have to find the value of x such that the probability is 0.15

$P( X > x) = P( z > \displaystyle\frac{x - 225}{43})=0.15$

$= 1 -P( z \leq \displaystyle\frac{x - 225}{43})=0.15$

$=P( z \leq \displaystyle\frac{x - 225}{43})=0.85$

Calculation the value from standard normal z table, we have,

$P(z < 1.036) = 0.85$

$\displaystyle\frac{x - 225}{43} = 1.036\\\\x = 269.548 \approx 269.55$

Thus, the coach should start recruiting players with weight 269.55 pounds or more.

3 0

3 years ago