Question

(2sin60°)(3tan60°)—(4tan45°)(2cos45°)​

Answer 1

Answer:

$9 - 4\sqrt{2}$

Step-by-step explanation:

sin60° = $\frac{\sqrt{3} }{2}$

tan60° = $\sqrt{3}$

tan45° = 1

cos45° = $\frac{1}{\sqrt{2} }$

(2sin60°)(3tan60°) - (4tan45°)(2cos45°)

now substitute the values of each trigonometrical angles

$(2*\frac{\sqrt{3} }{2} )(3*\sqrt{3} ) - (4*1)(2*\frac{1}{\sqrt{2} } )$

$\sqrt{3} * (3\sqrt{3}) - 4*(\frac{2}{\sqrt{2} } )$

$3*3 - 4*\frac{2}{\sqrt{2} } *\frac{\sqrt{2} }{\sqrt{2} }$

$9 - 4 *\frac{2\sqrt{2} }{2}$

$9 - 4 * \sqrt{2}$

$9 - 4\sqrt{2}$