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3 years ago

Suppose y varies directly as x, and y =15 when x = 3. Find the constant of variation (k).

Mathematics

1 answer:

vovangra [49]3 years ago

8 0

Answer:

k = 5

Step-by-step explanation:

y = kx

15 = k(3)

k = 15/3

k = 5

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If you have a lowest score of 21 and a range of 47, your highest score will be:________

aalyn [17]

Answer: 68

Step-by-step explanation:

range=47 lowest score = 21 let highest score =x

Range=highest score - lowest score

47 = x - 21

x = 47 + 21

x = 68

Therefore the highest score is 68

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3 years ago

Meghan has a beginning balance of $750 in her checking account. She writes a check for $150 and has a debit transaction of $135.

tatuchka [14]

Her new balance is her new balance would be 435
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750-150-135=435

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3 years ago

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5) x-y+6; use x = 6, and y = 1

ankoles [38]

Answer:

-1

Step-by-step explanation:

substitute x for 6 and y for 1

which will be 6-1+6

using BODMAS

6-(1+6)

6-7= -1

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3 years ago

Tim measures the length of four grasshoppers in his backyard: 5/4 cm, 7/4 cm, 9/4 cm, and 3/4 cm. What is the average length.

katrin [286]

Answer:6

Step-by-step explanation: add up all the fractions. The answer will be 24/4. Divide 24/4 equals 6.

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3 years ago

What is the simplified form of the following expression?

USPshnik [31]

Option C:

$$\frac{\sqrt[3]{100 x}}{5}=\sqrt[3]{\frac{4 x}{5}}$

Solution:

Given expression is

$$\sqrt[3]{\frac{4 x}{5}}$

Note: $\sqrt[3]{125}=\sqrt[3]{{5^3}} = 5$

To find the correct expression for the above simplified expression.

Option A: $\frac{\sqrt[3]{4 x}}{5}$

5 can be written as $\sqrt[3]{125}$ .

$$\frac{\sqrt[3]{4 x}}{5}=\frac{\sqrt[3]{4 x}}{\sqrt[3]{125} }$

$$=\sqrt[3]{\frac{4x}{125} }$

It is not the given simplified expression.

Option B: $\frac{\sqrt[3]{20 x}}{5}$

$$\frac{\sqrt[3]{20 x}}{5}=\frac{\sqrt[3]{20 x}}{\sqrt[3]{125} }$

$$=\sqrt[3]{\frac{20x}{125} }$

Cancel the common factor in both numerator and denominator.

$$=\sqrt[3]{\frac{4x}{25} }$

It is not the given simplified expression.

Option C: $\frac{\sqrt[3]{100 x}}{5}$

$$\frac{\sqrt[3]{100 x}}{5}=\frac{\sqrt[3]{100 x}}{\sqrt[3]{125} }$

$$=\sqrt[3]{\frac{100x}{125} }$

Cancel the common factor in both numerator and denominator.

$$=\sqrt[3]{\frac{4 x}{5}}$

It is the given simplified expression.

Option D: $\frac{\sqrt[3]{100 x}}{125}$

$$\frac{\sqrt[3]{100 x}}{125}=\frac{\sqrt[3]{100 x}}{5^3}$

It is not the given simplified expression.

Hence Option C is the correct answer.

$$\frac{\sqrt[3]{100 x}}{5}=\sqrt[3]{\frac{4 x}{5}}$

3 0

3 years ago