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lora16 [44]
3 years ago
13

Integrate[Exp[Power[sinx,2]]sin2x,x]

Mathematics
1 answer:
Otrada [13]3 years ago
5 0

Answer:

e^{sin²x}+c

Step-by-step explanation:

\int e^{sin^2x} sin 2x dx=?

is this statement?

if so

then

put~sin^2x=t\\differentiate\\2 sin ~x~cos~x~dx=dt\\sin~2x ~dx=dt\\\int e^t~dt=e^t+c\\=e^{sin^2x}+c

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