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GalinKa [24]
3 years ago
9

Please help! I need to finish this before the cutoff!!!!!

Mathematics
1 answer:
katrin2010 [14]3 years ago
7 0

Answer:

im not 100% sure but i think its the last one

D

im not 100% sure though

Step-by-step explanation:

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Kevin weighed his loaded truck at a weigh station. It weighed 14 tons 500 lbs 9 oz. His empty truck weighed 2 tons 600 lbs 12 oz
LenaWriter [7]
None of these are correct my calculations are 11 tons 2138 Ibs 28 oz
7 0
3 years ago
Roland's Boat Tours sells deluxe and economy seats for each tour it conducts. In order to complete a tour, at least 14 economy s
leonid [27]
The maximum profit would be $1325. Since they make less profit on deluxe seats, you want to get as few of those as possible. You also want to get as many people on the boat as possible, which is 45. The minimum number of deluxe seats you could sell is 5, so that's what we'll use for the max. profit. They make $25 off of each of those seats so 5 times $25 is $125. That leaves 40 economy seats, with a profit of $30 per seat. You have 40 spots left open, so we'll sell 40 economy seats, which will meet your minimum of 14 economy seats. 40 times $30 is $1200. Add $125 and $1200 to get $1325 and you have your maximum profit!
4 0
3 years ago
Santa Claus is assigning elves to work an eight-hour shift making toy trucks. Apprentice earn five candy canes per hour but can
dimaraw [331]

Answer:

  (a) 5 senior, 4 apprentice

  (b) 368 per shift

  (c) 7.5 senior, 0 apprentice

Step-by-step explanation:

The problem can be described by two inequalities. On describes the limit on the number of elves in the shop; the other describes the limit on the total payroll. Let x and y represent the number of apprentice and senior elves, respectively. Then the inequalities for the first scenario are ...

  x + y ≤ 9 . . . . . . . . . . . . total number of elves in the shop

  5x +8y ≤ 480/8 . . . . . . candy canes per hour paid to elves

These two inequalities are graphed in the first attachment. They describe a solution space with vertices at ...

  (x, y) = (0, 7.5), (4, 5), (9, 0)

__

(a) Santa wants to  maximize the output of trucks, so wants to maximize the function t = 4x +6y.

At the vertices of the solution space, the values of this function are ...

  t(0, 7.5) = 45

  t(4, 5) = 46

  t(9, 0) = 36

Output of trucks is maximized by a workforce of 4 apprentice elves and 5 senior elves.

__

(b) The above calculations show 46 trucks per hour can be made, so ...

  46×8 = 368 . . . trucks in an 8-hour shift

__

(c) The new demands change the inequalities to ...

  x + y ≤ 8 . . . . . . number of workers

  7x +8y ≤ 60 . . . total wages (per hour)

The vertices of the feasible region for these condtions are ...

  (x, y) = (0, 7.5), (4, 4), (8, 0)

From above, we know the truck output will be maximized at the vertex (x, y) = (0, 7.5). However, we know we cannot have 7.5 senior elves working in the shop. We can have 7 or 8 elves working.

If the workforce must remain constant, truck output is maximized by a workforce of 7 senior elves.

If the workforce can vary through the shift, truck output is maximized by adding one more senior elf in the shop for half a shift.

Santa should assign 7 senior elves for the entire shift, and 8 senior elves (one more) for half a shift.

_____

<em>Comment on apprentice elf wages</em>

At 5 candy canes for 4 trucks, apprentice elves produced trucks for a cost of 1.25 candy canes per truck. At 8 candy canes for 6 trucks, senior elves produced trucks for a cost of about 1.33 candy canes per truck. The reason for employing senior elves in the first scenario is that their productivity is 1.5 times that of apprentice elves while their cost per truck is about 1.07 times that of apprentice elves.

After the apprentice elves wages were increased, their cost per truck is 1.75 candy canes per truck, but their productivity hasn't changed. They have essentially priced themselves out of a job, because they are not competitive with senior elves.

5 0
3 years ago
A school  surveys 100 students to find out their favorite football team.  Seventy - one of the students said the Dallas Cowboys.
almond37 [142]
So out of 100 questioned 71 said Dallas Cowboys , that means 71% did  , now we have to work out 71% of 1200 which is 852 
3 0
3 years ago
A triangle has side lengths of n, n – 3, and 2(n − 2). If the perimeter of the triangle is at least 37 units, what is the value
Vilka [71]

Answer:

n = 11

Step-by-step explanation:

The side length of a triangle are n,n-3 and 2(n-2).

The perimeter of the triangle, P = 37 units

We need to find the value of n.

Perimeter = sum of all sides

n+n-3 +2(n-2) = 37

2n-3+2n-4 = 37

4n -7 = 37

4n = 37+7

4n = 44

n = 11

So, the value of n is 11.

3 0
3 years ago
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