(tan(<em>x</em>) + cot(<em>x</em>)) / (tan(<em>x</em>) - cot(<em>x</em>)) = (tan²(<em>x</em>) + 1) / (tan²(<em>x</em>) - 1)
… = (sin²(<em>x</em>) + cos²(<em>x</em>)) / (sin²(<em>x</em>) - cos²(<em>x</em>))
… = -1/cos(2<em>x</em>)
Then as <em>x</em> approaches <em>π</em>/2, the limit is -1/cos(2•<em>π</em>/2) = -sec(<em>π</em>) = 1.
Missing part in the heading of the question:For this question, use the diagram shown. The diagram shows the result of constructing a copy of an angle adjacent to one of the rays of the original angles. Assume the pattern continues.
Answer:measure of each angle = 24°
Explanation:The diagram shows two angles, if we add 13 more copies, the number of angles would be 15 angles
Now, when the 15 angles are drawn, the last angle would overlap with the first horizontal ray.
This means that the angles form one complete rotation around the point.
This means that the sum of the 15 angles together is 360°.
We know the all 15 angles are equal. Assume that the measure of each is x.
15 x = 360
x = 360 / 15
x = 24°
Hope this helps :)
Two hundred ten thousand and fifty is written as 210,050
Nineteen-hundredths is written as 19/100 or 0.19
So, the whole number is written as 210050.19
Answer:

Step-by-step explanation:
Given

Required
Determine the equation for the model
Represent the number of hours with h and the miles with m.
Using distance formula:

In this case, it is:

So, we have:


Answer:
Step-by-step explanation:
In Δ AFB,
∠AFB + ∠ABF + ∠A = 180 {Angle sum property of triangle}
90 + 48 + ∠1 = 180
138 + ∠1 = 180
∠1 = 180 - 138
∠1 = 42°
FC // ED and FD is transversal
So, ∠CFD ≅∠EDF {Alternate interior angles are congruent}
∠2 = 39°
In ΔFCD,
∠2 + ∠3 + ∠FCD = 180
39 + ∠3 + 90 = 180
129 +∠3 = 180
∠3 = 180- 129
∠3 = 51°