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3 years ago

Given that f(x) = 2x − 5, find the value of x that makes f(x) = 15. (5 points)

Mathematics

1 answer:

Katena32 [7]3 years ago

3 0

Answer:

Step-by-step explanation:2(10) -5

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Find the greatest common factor of -30x 4 yz 3 and 75x 4 z 2.

kicyunya [14]

If you combine -30 and +75 that will be 40. so GCF will be 40

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3 years ago

If you horizontally stretch the linear parent function, f(x) = x, by a factor of 3, what is the equation of the new function?

vekshin1

The correct answer is C

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2 years ago

If a/b < c/d with b > 0, d > 0, prove that a+c / b+d lies between the two fractions a/b and c/d .

Tems11 [23]

Divide through everything by b :

$\dfrac{a+c}{b+d} = \dfrac{\dfrac ab + \dfrac cb}{1 + \dfrac db}$

Since a/b < c/d, it follows that

$\dfrac{a+c}{b+d} < \dfrac{\dfrac cd+\dfrac cb}{1 + \dfrac db}$

Multiply through everything on the right side by b/d to get

$\dfrac{a+c}{b+d} < \dfrac{\dfrac{bc}{d^2}+\dfrac cd}{\dfrac bd+1} = \dfrac{\dfrac cd\left(\dfrac bd+1\right)}{\dfrac bd+1} = \dfrac cd$

and so (a + c)/(b + d) < c/d.

For the other side, you can do something similar and divide through everything by d :

$\dfrac{a+c}{b+d} = \dfrac{\dfrac ad + \dfrac cd}{\dfrac bd + 1}$

and a/b < c/d tells us that

$\dfrac{a+c}{b+d} > \dfrac{\dfrac ad + \dfrac ab}{\dfrac bd + 1}$

Then

$\dfrac{a+c}{b+d} > \dfrac{\dfrac ab + \dfrac{ad}{b^2}}{1 + \dfrac db} = \dfrac{\dfrac ab\left(1+\dfrac db\right)}{1 + \dfrac db} = \dfrac ab$

and so (a + c)/(b + d) > a/b.

Then together we get the desired inequality.

5 0

2 years ago

\dfrac {15}k

Monica [59]

Answer:

Step-by-step explanation:

8 0

2 years ago

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Simplify the following (1 1/2) ^-2

Serjik [45]

Answer:

1/2.25 or 4/9

Step-by-step explanation:

6 0

2 years ago