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3 years ago

Help me plz it’s due today

Mathematics

2 answers:

adelina 88 [10]3 years ago

7 0

The answer is A
:)))))))

Serggg [28]3 years ago

3 0

Answer:

Step-by-step explanation: Your salary will be greater than or equal to $46,000.

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adoni [48]

Answer:

y = |x| - 1

Step-by-step explanation:

The difference between the parent function (y=|x|) and the graph, is that the graph is 1 unit down. y = |x| -1 has the parent function 1 unit down

3 0

2 years ago

Read 2 more answers

2. A student usually saves $20 per month. He would like to reach a goal of saving $350 in 12 months. The student writes the equa

Zigmanuir [339]

Answer:

x = 9.17 (nearest hundredth)

The variable x is the amount the student needs to save each month in addition to his usual saved amount of $20.

Step-by-step explanation:

350 = 12(x + 20)

Multiply out brackets: 350 = 12x + 240

Subtract 240 from both sides: 110 = 12x

Divide both sides by 12: 9 1/6 = x

x = 9.17 (nearest hundredth)

The variable x is the amount the student needs to save each month in addition to his usual saved amount of $20.

3 0

2 years ago

Please consider the following values for the variables X and Y. Treat each row as a pair of scores for the variables X and Y (wi

Studentka2010 [4]

Answer:

The Pearson's coefficient of correlation between the is 0.700.

Step-by-step explanation:

The correlation coefficient is a statistical degree that computes the strength of the linear relationship amid the relative movements of the two variables (i.e. dependent and independent).It ranges from -1 to +1.

The formula to compute correlation between two variables <em>X</em> and <em>Y</em> is:

$r(X, Y)=\frac{Cov(X, Y)}{\sqrt{V(X)\cdot V(Y)}}$

The formula to compute covariance is:

$Cov(X, Y)=n\cdot \sum XY-\sum X \cdot\sum Y$

The formula to compute the variances are:

$V(X)=n\cdot\sum X^{2}-(\sum X)^{2}\\V(Y)=n\cdot\sum Y^{2}-(\sum Y)^{2}$

Consider the table attached below.

Compute the covariance as follows:

$Cov(X, Y)=n\cdot \sum XY-\sum X \cdot\sum Y$

$=(5\times 165)-(30\times 25)\\=75$

Thus, the covariance is 75.

Compute the variance of X and Y as follows:

$V(X)=n\cdot\sum X^{2}-(\sum X)^{2}\\=(5\times 226)-(30)^{2}\\=230\\\\V(Y)=n\cdot\sum Y^{2}-(\sum Y)^{2}\\=(5\times 135)-(25)^{2}\\=50$

Compute the correlation coefficient as follows:

$r(X, Y)=\frac{Cov(X, Y)}{\sqrt{V(X)\cdot V(Y)}}$

$=\frac{75}{\sqrt{230\times 50}}$

$=0.69937\\\approx0.70$

Thus, the Pearson's coefficient of correlation between the is 0.700.

5 0

3 years ago

For which values of p and q, will the following pair of linear equations have infinitely many

Tema [17]

In order to have infinitely many solutions with linear equations/functions, the two equations have to be the same;
In accordance, we can say:
(2p + 7q)x = 4x [1]
(p + 8q)y = 5y [2]
2q - p + 1 = 2 [3]
All we have to do is choose two equations and solve them simultaneously (The simplest ones for what I'm doing and hence the ones I'm going to use are [3] and [2]):
Rearrange in terms of p:
p + 8q = 5 [2]
p = 5 - 8q [2]
p + 2 = 2q + 1 [3]
p = 2q - 1 [3]
Now equate rearranged [2] and [3] and solve for q:
5 - 8q = 2q - 1
10q = 6
q = 6/10 = 3/5 = 0.6

Now, substitute q-value into rearranges equations [2] or [3] to get p:
p = 2(3/5) - 1
p = 6/5 - 1
p = 1/5 = 0.2

3 0

3 years ago

On the day of his 18th birthday harry decided to start saving money regularly

Veseljchak [2.6K]

We have been given that on the day of his 18th birthday Harry decided to start saving money regularly . Starting on that day, he could save 30.00 on the same date every month. We are asked to find the amount saved by the day before Harry's 60th birthday.

First of all, we will find years from 18 years to 60 years.

$\text{Years}=60-18=42$