Explanation:
The given precipitation reaction will be as follows.
Here, AgCl is the precipitate which is formed.
It is known that molarity is the number of moles present in a liter of solution.
Mathematically, Molarity = 
It is given that volume is 1.14 L and molarity is 0.269 M. Therefore, calculate number of moles as follows.
Molarity =
0.269 M = 
no. of moles = 0.306 mol
As molar mass of AgCl is 143.32 g/mol. Also, relation between number of moles and mass is as follows.
No. of moles = 
0.307 mol = 
mass = 43.99 g
Thus, we can conclude that mass of precipitate produced is 43.99 g.
Answer:
Hg(NO₃)₂(aq) + Na₂SO₄(aq) → 2NaNO₃(aq) + HgSO₄(s)
Moles of Hg(NO₃)₂ = 55.42 / 324.7 ==> 0.1707 moles
Moles of Na₂SO₄ = 16.642 / 142.04 ==> 0.1172 moles
Limiting reagent is Na₂SO₄ as it controls product formation
Moles of HgSO₄ formed = 0.1172 moles
= 0.1172 x 296.65
= 34.757g
Explanation:
There are 4 significant digits: 3405.
Answer:
D)groups 1 and 2
Explanation:
The s-block of elements are made up of those chemical elements we can find in groups 1 and 2 on the periodic table.
A periodic table of element is based on the periodic law which states that "the properties of elements are a periodic function of their atomic number".
In the table;
- elements having the same number of electrons in the outermost shell are placed over one another in vertical columns.
- each resulting vertical column is called a group or family.
- resulting horizontal rows are known as periods.
The s-block consists of elements in groups 1 and 2 having an outermost ""ns"" shell configuration. They are predominantly metals.
For Option A, groups 3-12 is the D-block
Option B, group 18 is filled with noble gases and it makes up the p-block
Option C, group 13-18 is makes up the p-block too.
So, the s-block is made up group 1 and 2 elements.
