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Elena-2011 [213]
3 years ago
11

Definition: This is an important principle of the scientific method in which an experiment can accurately be reproduced by an in

dependent researcher. Replication shows that test results can be reproduced with different scientists and lab equipment.
Chemistry
1 answer:
zysi [14]3 years ago
7 0

Answer:

Replicate.

Explanation:

Replicate: This is an important principle of the scientific method in which an experiment can accurately be reproduced by an independent researcher. Replication shows that test results can be reproduced with different scientists and lab equipment.

Hence, when test experiments are performed or conducted and the same results are gotten, it ultimately implies that the research is statistically significant and correct. A theory can be developed by the repetition or replication of a hypothesis.

In scientific process, researchers do not rely on a single test. They replicate tests over and over to see if they will get the same results.

In conclusion, if an experiment, investigation or findings can't be replicated then the method of testing isn't sufficient, theoretical and not reliable for use.

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When adjusted for any changes in ΔHΔH and ΔSΔS with temperature, the standard free energy change ΔG∘TΔGT∘Delta G_{T}^{\circ} at
STALIN [3.7K]

The equilibrium constant is 0.0022.

Explanation:

The values given in the problem is

ΔG° = 1.22 ×10⁵ J/mol

T = 2400 K.

R = 8.314 J mol⁻¹ K⁻¹

The Gibbs free energy should be minimum for a spontaneous reaction and equilibrium state of any reaction is spontaneous reaction. So on simplification, the thermodynamic properties of the equilibrium constant can be obtained as related to Gibbs free energy change at constant temperature.

The relation between Gibbs free energy change with equilibrium constant is ΔG° = -RT ln K

So, here K is the equilibrium constant. Now, substitute all the given values in the corresponding parameters of the above equation.

We get,

1.22 * 10^{5} = - 8.314* 2400 * ln K

\\ 1.22 * 10^{5} = -19953.6 * ln K

ln K = \frac{-1.22*10^{5} }{19953.6} =-6.114\\\\k =e^{-6.114}=0.0022

So, the equilibrium constant is 0.0022.

4 0
3 years ago
Are alchemy and chemistry the same
Anit [1.1K]

Are alchemy and chemistry the same: No

<u>Explanation:</u>

Alchemy and chemistry differ from each other. Their main difference lies in the concepts that they are based on. Alchemy has the base of viewing the reality of nature supernaturally. Chemistry has a base of viewing the reality in a natural way.

Protoscience is the name given for Alchemy. This is because that alchemy usually focuses on the traditional things like procedures and  terminologies. Chemistry always focuses on the matter and their transformations. The matter and its transformations are dealt with chemistry.

5 0
3 years ago
What is the ∆G for the following reaction between O3 and O2? 3O2(g) 2O3(g) Given: O3: ∆H = 285.4 kJ ∆S = -137.14 J/K)
Natali [406]
We’ll be using the equation:
dG = dH - TdS (replace ‘d’ with triangle)

I’m going to assume 0 degrees Celsius.
At 0 C (273 K):

dG = dH - TdS
dG = (285,400 J) - (273 K)(-137.14 J/K)
dG = 285,400 J + 37,439.2 J
dG = 322,839.2 J or 322.84 kJ

The dG of this reaction is +322.84 kJ. This reaction is not considered spontaneous.

This answer, in this instance, would be D. If the temperature used in the question is not 0 degrees C, replace the temperature that I used for calculation with the Kelvin temperature given in the problem (K = C + 273), and simplify to find the answer.
6 0
3 years ago
What is science of love?​
shtirl [24]

science of love

,EXPLANATION:

The initial happy feelings of being in love is stimulated by 3 chemicals in the brain: noradrenaline that stimulates adrenaline production causing that racing heart and sweaty palms; dopamine, the feel-good chemical; and phenylethylamine that is released when we're near our crush, giving us butterflies in our tummies.

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6 0
3 years ago
Six moles of an ideal gas are in a cylinder fitted at one end with a movable piston. the initial temperature of the gas is 27.0c
Alla [95]

We have to know final temperature of the gas after it has done 2.40 X 10³ Joule of work.

The final temperature is: 75.11 °C.

The work done at constant pressure, W=nR(T₂-T₁)

n= number of moles of gases=6 (Given), R=Molar gas constant, T₂= Final temperature in Kelvin, T₁= Initial temperature in Kelvin =27°C or 300 K (Given).

W=2.4 × 10³ Joule (Given)

From the expression,

(T₂-T₁)=\frac{W}{nR}

(T₂-T₁)= \frac{2.40 X 10^{3} }{6 X 8.314}

(T₂-T₁)= 48.11

T₂=300+48.11=348.11 K= 75.11 °C

Final temperature is 75.11 °C.


6 0
3 years ago
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