Answer:
<h2>1 < x < 6 ⇒ x ∈ (1, 6)</h2>
Step-by-step explanation:
3x - 8 > -5 <em>add 8 to both sides</em>
3x > 3 <em>divide both sides by 3</em>
x > 1
2x - 7 < 5 <em>add 7 to both sides</em>
2x < 12 <em>divide both sides by 2</em>
x < 6
From x > 1 and x < 6 we have the solution 1 < x < 6 ⇒ x ∈ (1, 6)
Answer:
Huh
Step-by-step explanation:
Answer:
Step-by-step explanation:
Assuming there is a punitive removal of one point for an incorrect response.
Five undiscernable choices: 20% chance of guessing correctly -- Expectation: 0.20*(1) + 0.80*(-1) = -0.60
Four undiscernable choices: 25% chance of guessing correctly -- Expectation: 0.25*(1) + 0.75*(-1) = -0.50
I'll use 0.33 as an approzimation for 1/3
Three undiscernable choices: 33% chance of guessing correctly -- Expectation: 0.33*(1) + 0.67*(-1) = -0.33 <== The approximation is a little ugly.
Two undiscernable choices: 50% chance of guessing correctly -- Expectation: 0.50*(1) + 0.50*(-1) = 0.00
And thus we see that only if you can remove three is guessing neutral. There is no time when guessing is advantageous.
One Correct Answer: 100% chance of guessing correctly -- Expectation: 1.00*(1) + 0.00*(-1) = 1.00
20 because when you do it that way when it is behind the decimal the numbers are always the opposite thousand hundred tens ones . tens hundreds thousands
