Answer:
NO amount of hour passed between two consecutive times when the water in the tank is at its maximum height
Step-by-step explanation:
Given the water tank level modelled by the function h(t)=8cos(pi t /7)+11.5. At maximum height, the velocity of the water tank is zero
Velocity is the change in distance with respect to time.
V = {d(h(t)}/dt = -8π/7sin(πt/7)
At maximum height, -8π/7sin(πt/7) = 0
-Sin(πt/7) = 0
sin(πt/7) = 0
Taking the arcsin of both sides
arcsin(sin(πt/7)) = arcsin0
πt/7 = 0
t = 0
This shows that NO hour passed between two consecutive times when the water in the tank is at its maximum height
(4,-2) because you would transfer the point the same distance away from the y axis just on the other side of it
to factor it the answer is (x+1)(x+1)
to simplify it the answer is x2+2x+1
idk if this helped or not but here you go
Answer:
x = -3
Step-by-step explanation:
2(x+4)=-7-3x
Distribute
2x+8 = -7-3x
Add 3x to each side
2x+3x+8=-7-3x+3x
5x +8 = -7
Subtract 8 from each side
5x+8-8 = -7-8
5x = -15
Divide each side by 5
5x/5 = -15/5
x = -3
