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SVETLANKA909090 [29]
3 years ago
15

How do you draw first angle of orthographic projection ​

Computers and Technology
1 answer:
attashe74 [19]3 years ago
5 0
Https://technologystudent.com/designpro/ortho1.htm
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Let A and B be two stations attempting to transmit on an Ethernet. Each has a steady queue of frames ready to send; A’s frames w
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Following are the solution to the given question:

Explanation:

Please find the complete and correct question in the attachment file.  

For Point a:

For the second round,

A is selects kA(2)  either 0 or 1, so for each of them, that is \frac{1}{2}.

B selects kB(2)\  from\  (0, 1, 2, 3) for each choice with the probability of \frac{1}{4}.

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\to P[A \ wins] = P[kA(2) < kB(2)]

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For Point b:

Throughout this example, kA(3) also selects to be either 0 or 1 with such a \frac{1}{2} probability. So, although B chooses kB(3) from (0, 1, 2, 3, 4, 5, 6, 7), the probabilities each are \frac{1}{8}:

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For point c:

Assume that B tries again 16 times (typical value), and it destroys. In addition, throughout the exponential background n is obtained at 10 when choosing k between 0 to 2n−1. The probability of A winning all 13 backoff events is: P[A \text{wins remaining races}] = 16\pi i =4P[A \ wins \ i |A \ wins \ i -1 ]

Let the k value kA(i) be A for the backoff race I select. Because A retains the breed

=(kA(i)] \cdot P[kA(i+ 1)< kB(i+ 1)] \geq P[kA(i) + 1

For point d:

Two stations A and B are supposed. They assume that B will try 16 times afterward. Even so, for A, 16 races were likely to also be won at a rate of 0.82 For Just higher expectations of three A, B, and C stations. For Station A, possibility to win all backoffs

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