Answer:
t≈8.0927
Step-by-step explanation:
h(t) = -16t^2 + 128t +12
We want to find when h(t) is zero ( or when it hits the ground)
0 = -16t^2 + 128t +12
Completing the square
Subtract 12 from each side
-12 = -16t^2 + 128t
Divide each side by -16
-12/-16 = -16/-16t^2 + 128/-16t
3/4 = t^2 -8t
Take the coefficient of t and divide it by 8
-8/2 = -4
Then square it
(-4) ^2 = 16
Add 16 to each side
16+3/4 = t^2 -8t+16
64/4 + 3/4= (t-4)^2
67/4 = (t-4)^2
Take the square root of each side
±sqrt(67/4) =sqrt( (t-4)^2)
±1/2sqrt(67) = (t-4)
Add 4 to each side
4 ±1/2sqrt(67) = t
The approximate values for t are
t≈-0.092676
t≈8.0927
The first is before the rocket is launched so the only valid answer is the second one
Answer:
$64,000
Step-by-step explanation:
Friday, 45 / 9 = 5
So the investment will double 5 times
First time
2,000 (starting investment) × 2 = 4000
Second time
4000 × 2 = 8000
Third time
8000 × 2 = 16000
Fourth time
16000 × 2 = 32000
Fifth and final time
32000 × 2 = 64000
$64,000
Hi there!
First, you need to find the quotient of 4 and 13, obviously.
4/13 is equal to roughly 0.308.
Those grouping symbols around it tell you that you need to find the absolute value.
Absolute value is how far away a number is from 0 on a number line. 3, for example has a absolute value of 3, and -6 has an absolute value of 6.
So, the absolute value of 4/13 is about 0.308.
Hope this helps. :)
-Spagoot
