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Anon25 [30]
2 years ago
10

What is the domain of the linear parent function?

Mathematics
1 answer:
Tasya [4]2 years ago
4 0

Answer:

The parent function of linear functions is y=x and it passes through the origin.The domain and range of all linear functions are all real numbers.



Step-by-step explanation:

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1. Insert a rational number and an irrational numbers between <br><br> A)0.1 and 0.11
Zolol [24]
For this case we have the following definition:
 A real number can be a rational number or an irrational number.
 The rational numbers are those that can be expressed as the quotient of two integers, such as 3/4, -21/3, 5, 0, 1/2, while the irrational numbers are all the others.
 Between 0.1 and 0.11 we have:
 Rational number: 105/1000 = 0.105
 Irrational number: 01057685429832687
5 0
3 years ago
Why does the number 17 not belong with 26, 44, &amp; 65
kkurt [141]

17 is a prime number whereas 26,44 and 65 are the composite numbers.

<u>Step-by-step explanation:</u>

The number 17 does not belong with 26, 44 and 65.

Here 26 is divisible by 2 and 13.

44 is divisible by 2, 4 and 11.

65 is divisible by 5 and 13

But 17 is divisible by 1 and itself, that is it's a prime number, whereas the other numbers 26, 44 and 65 is divided by 1, itself and also by other numbers.

So 17 is a prime number whereas the 65, 26 and 44 are composite numbers.

7 0
3 years ago
For the functions f(x) = 2x – 3 and g(x) = 5x + 5, find (f • g)(x).
Nimfa-mama [501]

Answer:

f(g(x)) = 10x + 7

Step-by-step explanation:

(f . g)(x) = f(g(x)) is the composition of the functions f(x) and g(x).

f(g(x)) means that g(x) becomes the input for f.

Now, f(x) = 2x - 3 and g(x) = 5x + 5.

f(g(x)) = f(5x + 5)

         = 2((5x + 5) - 3)

         = 10x + 10 - 3

         = 10x + 7

f(g(x)) = 10x + 7 is the required answer.

5 0
4 years ago
Circle all the numbers that will round to 42.3 42.35 42.29 42.25 42.23 42.32
lions [1.4K]

Answer:

42.29, 42.25, 42.32

Step-by-step explanation:

7 0
4 years ago
Read 2 more answers
Two buildings on opposites sides of a highway are 3x^3- x^2 + 7x +100 feet apart. One building is 2x^2 + 7x feet from the highwa
iVinArrow [24]

Given:

Distance between two buildings = 3x^3- x^2 + 7x +100 feet apart.

Distance between highway and one building = 2x^2 + 7x feet.

Distance between highway and second building = x^3 + 2x^2 - 18 feet.

To find:

The standard form of the polynomial representing the width of the highway between the two building.

Solution:

We know that,

Width of the highway = Distance between two buildings - Distance of both buildings from highway.

Using the above formula, we get the polynomial for width (W) of the highway.

W=3x^3- x^2 + 7x +100-(2x^2 + 7x)-(x^3 + 2x^2 - 18)

W=3x^3- x^2 + 7x +100-2x^2-7x-x^3 -2x^2+18

Combining like terms, we get

W=(3x^3-x^3)+(- x^2 -2x^2-2x^2)+ (7x -7x)+(100 +18)

W=2x^3-5x^2+0+118

W=2x^3-5x^2+118

Therefore, the width point highway is 2x^3-5x^2+118.

8 0
3 years ago
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