Is this for real? Lol anyways I’m guessing B
Answer:
y = 52x + 400
Step-by-step explanation:
A linear model has the form y = mx + b
There are two variables: the <em>volume (y) of water </em>and the <em>number (x) of minutes</em> the pool has been filling. The volume of water depends on how long the pool is filling.
m = (y₂-y₁)/(x₂ -x₁)
x₁ = 0; y₁ = 400
x₂ = 8; y₂ = 816
m = (816 - 400)/(8 - 0)
m = 416/8
m = 52 gal/min
The initial value (b) is the volume at time zero.
b = 400 gal
The linear function is
y = 52x + 400
===============
<em>Volume after 20 min
</em>
y = 52×20 + 400
y = 1040 + 400
y = 1440 gal
The pool will contain 1440 gal in 20 min.
Decay because .078 is less that 1 meaning it goes down
That should be 125i. If you have a graphing calculator you should be able to just enter it into the calculator to solve lol
Answer:
F(a) = a² + 3a - 2
F(x-1) = x² + x -4
Step-by-step explanation:
Note:
Domain is missing, assume domain
F(a)
F(x-1)
Given:
F(x) = x² + 3x - 2
Computation:
1. F(x) = x² + 3x - 2
So,
⇒ F(a) = a² + 3a - 2
2. F(x-1) = (x-1)² + 3(x-1) - 2
F(x-1) = x² + 1 -2x + 3x - 3 - 2
F(x-1) = x² + x -4